Answer:
Required Volume is 22.47ml
Explanation:
To make 2.0L of 0.2M sulfuric acid required moles = 0.2 x 2 = 0.4 moles
To get 0.4 from 17.8M required quantity = 1000/17.8 x 0.4 = 22.47ml
Tan2(∅) ≡ 2tan(∅) / (1 - tan²∅)
Thus,
2tan(∅) / (1 - tan²(∅)) + tan(∅) = 0
2tan(∅) / (1 - tan²(∅)) = -tan(∅)
1 - tan²(∅) = -2
tan²(∅) = 3
∅ = tan⁻¹(√3)
∅ = 4nπ/3
Answer: 6.02 x 10^23
Explanation: Please look at the photo below for confirmation!
Answer:
-4.59°C
Explanation:
Let's see the formula for freezing point depression.
ΔT = Kf . m . i
ΔT = Freezing T° of pure solvent - Freezing T° of solution
Kf = Freezing constant. For water if 1.86°C/m
m = molality (moles of solute in 1kg of solvent)
i = Van't Hoff factor.
0°C - Freezing T° of solution = 1.86°C /m . 1.30m . 1.9
Freezing T° of solution = - (1.86°C /m . 1.30m . 1.9)
Freezing T° of solution = - (1.86°C/m . 1.30m . 1.9) → -4.59°C
NaCl → Na⁺ + Cl⁻
