Question

3. Given the following reactants: AgI + Fe(CO3)3 

Answer 1

Explanation:

The products of chemical reaction will be as follows.

      $AgI + Fe_{2}(CO_{3})_{3} \rightarrow FeI_{3} + Ag_{2}CO_{3}$

To balance the equation, we will count the number of atoms on both reactant and product sides as follows.

Number of atoms on reactant side are as follows.

• Ag = 1
• I = 1
• Fe = 2
• $CO_{3}$ = 3

Number of atoms on product side are as follows.

• Ag = 2
• I = 3
• Fe = 1
• $CO_{3}$ = 1

We will balance the equation by multiplying AgI by 6 on the reactant side and $FeI_{3}$ by 2 and $Ag_{2}CO_{3}$ by 3 on the product side. Therefore, balanced chemical equation will be as follows.

   $6AgI + Fe_{2}(CO_{3})_{3} \rightarrow 2FeI_{3} + 3Ag_{2}CO_{3}$

In this reaction, iron is replaced by silver and carbonate is replaced by iodide. Thus, it is a double displacement reaction.