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anygoal [31]
4 years ago
10

Which measurement of length is the smallest?

Chemistry
2 answers:
babymother [125]4 years ago
6 0
I guess A is the correct answer
guapka [62]4 years ago
5 0

Answer : The correct option is 9\times 10^{-6}m.

Explanation :

Length : It is defined as the measurement of any object from end to end.

The length is measured in many terms like in Meter, Centimeter, Kilometer, etc.

9\times 10^{-6}m=0.000009m

7\times 10^{-5}m=0.00007m

7\times 10^{1}m=7m

9\times 10^{2}m=90m

The higher the negative power of 10, the lower will be the value.

And the higher the positive power of 10, the higher will be the value.

Therefore, the smallest value of length is 9\times 10^{-6}m.

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C

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30cm^3 of a dilute solution of Ca(OH)2 required 11 cm^3 of 0.06 mol/dm^. Hcl for complete neutralization. Calculate the concentr
Alenkasestr [34]

Answer: Thus concentration of Ca(OH)_2 in mol/dm^3  is 0.011 and in g/dm^3 is 0.814

Explanation:

To calculate the concentration of Ca(OH)_2, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is Ca(OH)_2

We are given:

n_1=1\\M_1=0.06mol/dm^3\\V_1=11cm^3=0.011dm^3\\n_2=2\\M_2=?\\V_2=30cm^3=0.030dm^3         1cm^3=0.001dm^3

Putting values in above equation, we get:

1\times 0.06mol/dm^3\times 0.011dm^3=2\times M_2\times 0.030dm^3\\\\M_2=0.011mol/dm^3

The concentration in g/dm^3 is 0.011mol/dm^3\times 74g/mol=0.814g/dm^3

Thus concentration of Ca(OH)_2 is 0.011mol/dm^3 and 0.814g/dm^3

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