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elena-14-01-66 [18.8K]
3 years ago
15

How can you efficiently determine the number of atoms in a sample of an element?

Chemistry
1 answer:
nata0808 [166]3 years ago
3 0

Answer:

b. First determine the mass of the sample and then convert it to the number of atoms using Avogadro's number and the molar mass of the element.

Explanation:

a. First determine the mass of the sample and then convert it to the number of atoms using the molar mass of the element.  <em>FALSE. </em>As the mass is in grams and molar mass is in g/mol. This result in the moles of each element, not its number of atoms.

b. First determine the mass of the sample and then convert it to the number of atoms using Avogadro's number and the molar mass of the element.  <em>TRUE. </em>Mass and molar mass will result in moles of element. These moles could be converted in number of atoms using Avogadro's number that is in # atoms per mole.

c.Use atomic microscope to determine Avogadro's number, then determine the mass of the sample and convert it to the number of atoms.  <em>FALSE. </em>An atomic microscope is not used to determine Avogadro's number.

d.Use atomic microscope to count each atom. <em>FALSE. </em>There is not possible to count every single atom in an element. There are more atoms in a drop of water than stars in the sky.

I hope it helps!

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Explanation:

Secondary consumers are organisms that eat primary consumers for energy. Primary consumers are always herbivores, or organisms that only eat autotrophic plants.

Carnivores only eat other animals, and omnivores eat both plant and animal matter.

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3.00 moles of nitrogen and 4.00 moles of oxygen are placed in a 35.0 L container at a temperature of 298 K. What is the pressure
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In a chemical reaction, what is defined as the difference between the potential energy of the products and the potential energy
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(2-2) Looking at the chemical formula CaF2 (calcium fluoride), what do you think this substance is made of? (Choose ALL that app
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Answer:

Metal

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Explanation:

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3 years ago
"46.7 g of water at 80.6 oC is added to a calorimeter that contains 45.33 g of water at 40.6 oC. If the final temperature of the
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<u>Answer:</u> The specific heat of calorimeter is 30.68 J/g°C

<u>Explanation:</u>

When hot water is added to the calorimeter, the amount of heat released by the hot water will be equal to the amount of heat absorbed by cold water and calorimeter.

Heat_{\text{absorbed}}=Heat_{\text{released}}

The equation used to calculate heat released or absorbed follows:

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[(m_2\times c_2)+c_3](T_{final}-T_2)       ......(1)

where,

q = heat absorbed or released

m_1 = mass of hot water = 46.7 g

m_2 = mass of cold water = 45.33 g

T_{final} = final temperature = 59.4°C

T_1 = initial temperature of hot water = 80.6°C

T_2 = initial temperature of cold water = 40.6°C

c_1 = specific heat of hot water = 4.184 J/g°C

c_2 = specific heat of cold water = 4.184 J/g°C

c_3 = specific heat of calorimeter = ? J/g°C

Putting values in equation 1, we get:

46.7\times 4.184\times (59.4-80.6)=-[(45.33\times 4.184)+c_3](59.4-40.6)

c_3=30.68J/g^oC

Hence, the specific heat of calorimeter is 30.68 J/g°C

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