All categories

3 years ago

How can you efficiently determine the number of atoms in a sample of an element?

Chemistry

1 answer:

nata0808 [166]3 years ago

3 0

Answer:

b. First determine the mass of the sample and then convert it to the number of atoms using Avogadro's number and the molar mass of the element.

Explanation:

a. First determine the mass of the sample and then convert it to the number of atoms using the molar mass of the element. FALSE. As the mass is in grams and molar mass is in g/mol. This result in the moles of each element, not its number of atoms.

b. First determine the mass of the sample and then convert it to the number of atoms using Avogadro's number and the molar mass of the element. TRUE. Mass and molar mass will result in moles of element. These moles could be converted in number of atoms using Avogadro's number that is in # atoms per mole.

c.Use atomic microscope to determine Avogadro's number, then determine the mass of the sample and convert it to the number of atoms. FALSE. An atomic microscope is not used to determine Avogadro's number.

d.Use atomic microscope to count each atom. FALSE. There is not possible to count every single atom in an element. There are more atoms in a drop of water than stars in the sky.

I hope it helps!

You might be interested in

What is the Representative Particles in 1.00 mol of atomic nitrogen

docker41 [41]

Answer:

a molecule.

Explanation:

5 0

2 years ago

Explain how you were able to use your knowledge of how different types of blood react with anti A, anti B, and anti Rh antibodie

dybincka [34]

Depending upon the clumping reaction with anti A , anti B and anti Rh antibodies the blood types are determined.

Explanation:

Agglutination (clumping) will occur when blood that contains the particular antigen is mixed with the particular antibody.

A+ have Agglutination with Anti-A ,Anti-Rh and No agglutination with Anti-B.

A- have Agglutination with Anti-A and No agglutination with Anti-B and Anti-Rh.

B+ have Agglutination with Anti-B Anti-Rh and No agglutination with Anti-A.

B- have Agglutination with Anti-B and No agglutination with Anti-B and Anti-Rh.

Rh+ have Agglutination with Anti-A and Anti-Rh and No agglutination with Anti-B.

Rh- have No Agglutination with Anti-A and Anti-B and Anti-Rh.

3 0

3 years ago

Muriatic acid, an industrial grade of concentrated HCl, is used to clean masonry and cement. Its concentration is 11.7 M. For ro

spin [16.1K]

383 mL of 3.50 M muriatic acid solution

Explanation:

First we calculate the number of moles of HCl:

number of moles = mass / molecular weight

number of moles of HCl = 47.7 / 35.5 = 1.34 moles

Now to determine the volume of the 3.50 M muriatic acid (clorhidric acid) solution, we use the following formula:

molar concentration = number of moles / volume (L)

volume (L) = number of moles / molar concentration

volume of the muriatic acid solution = 1.34 / 3.5 = 0.383 L = 383 mL

Learn more about:

molar concentration

brainly.com/question/10270173

brainly.com/question/10608366

#learnwithBrainly

3 0

3 years ago

A reaction mixture initially contains 0.86 atm NO and 0.86 atm SO3. Determine the equilibrium pressure of NO2 if Kp for the reac

dlinn [17]

Explanation:

Reaction equation for this reaction is as follows.

$NO(g) + SO_{3}(g) \rightarrow NO_{2}(g) + SO_{2}(g)$

It is given that $K_{p}$ = 0.0118.

According to the ICE table,

$NO(g) + SO_{3}(g) \rightarrow NO_{2}(g) + SO_{2}(g)$

Initial: 0.86 0.86 0 0

Change: -x -x +x +x

Equilibrium: 0.86 - x 0.86 - x x x

Hence, value of $K_{p}$ will be calculated as follows.

$K_{p} = \frac{P_{NO_{2}} \times P_{SO_{3}}}{P_{NO} \times P_{SO_{3}}}$

0.0118 = $\frac{x \times x}{(0.86 - x)^{2}}$

x = 0.084 atm

Thus, we can conclude that $P_{NO_{2}}$ is 0.084 atm.

4 0

4 years ago

Brainliest!!!!!!Parking lots and other man made ground coverings may increase erosion around there edges

ollegr [7]

Answer:

true trust ong gotta be true fff

4 0

3 years ago