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3 years ago

What is the displacement of the particle in the time interval 5 seconds to 8 seconds?

2 answers:

5 0

The displacement of the particle in the time interval 5 seconds to 8 seconds will be 1.5 meters.
Displacement is a vector quantity; meaning it has both magnitude and direction; magnitude being the distance between the interval at 5 seconds and position at 8 seconds, while the direction is from position at 5 second to position at 8 second. This is irrespective of the route followed during the time interval.

Gekata [30.6K]3 years ago

3 0

Answer:

1.5 meters plato users ;)

Explanation:

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consider the hypothetical observation irregular galaxies outside the local group are moving toward us. from part a, this observa

alina1380 [7]

Answer:

spiral galaxies move away from us 10% faster than elliptical galaxies at the same distances; irregular galaxies outside the Local Group are moving toward us; galaxy speeds are faster in summer than in winter

Explanation:

This may help I'm not sure.

3 0

2 years ago

A closed, rigid tank fitted with a paddle wheel contains 2 kg of air, initially at 300 K. During an interval of 5 minutes, the p

anzhelika [568]

Answer:

The final temperature of the air is $T_2= 605 K$

Explanation:

We can start by doing an energy balance for the closed system

$\Delta KE+\Delta PE+ \Delta U = Q - W$

where

$\Delta KE$ = the change in kinetic energy.

$\Delta PE$ = the change in potential energy.

$\Delta U$ = the total internal energy change in a system.

Q = the heat transferred to the system.

W = the work done by the system.

We know that there are no changes in kinetic or potential energy, so $\Delta KE = 0$ and $\Delta PE=0$

and our energy balance equation is $\Delta U = Q - W$

We also know that the paddle-wheel transfers energy to the air at a rate of 1 kW and the system receives energy by heat transfer at a rate of 0.5 kW, for 5 minutes.

We use this information to calculate the total internal energy change $\Delta U=W+Q$ using the energy balance equation.

We convert the interval of time to seconds $t = 5 \:min = 300\:s$

$\Delta \dot{U}=\dot{W}+ \dot{Q}\\=\Delta U=(W+ Q)\cdot t$

$\Delta U=(1 \:kW+0.5\:kW)\cdot 300\:s\\\Delta U=450 \:kJ$

We can use the change in specific internal energy $\Delta U = m(u_2-u_1)$ to find the final temperature of the air.

We are given that $T_1=300 \:K$ and the air can be describe by ideal gas model, so we can use the ideal gas tables for air to determine the initial specific internal energy $u_1$

$u_1=214.07\:\frac{kJ}{kg}$

Next, we will calculate the final specific internal energy $u_2$

$\Delta U = m(u_2-u_1)\\\frac{\Delta U}{m} =u_2-u_1$

$\frac{\Delta U}{m} =u_2-u_1\\u_2=u_1+\frac{\Delta U}{m}$

$u_2=214.07 \:\frac{kJ}{kg} +\frac{450 \:kJ}{2 \:kg}\\u_2= 439.07 \:\frac{kJ}{kg}$

With the value $u_2=439.07 \:\frac{kJ}{kg}$ and the ideal gas tables for air we make a regression between the values $u = 434.78 \:\frac{kJ}{kg},T=600 \:K$ and $u = 442.42 \:\frac{kJ}{kg}, T=610 \:K$ and we find that the final temperature $T_2$ is 605 K.

3 0

3 years ago

Anyone! Help me! (:o

Gnom [1K]

You have written the answer within your question.

mass of 1kg metal is "1 kilogram"

but when you talk about it's weight
then,
it's weight is 9.8 Newton.

5 0

3 years ago

Read 2 more answers

How is it that even light precipitation can still cause the collection of large amounts of water.

Firdavs [7]

Answer:

the heat of the light.

Explanation:

no matter the light, there's always heat being produced from it. and heat makes liuqid rise

4 0

3 years ago

Explain the difference between balanced forces and action and reaction forces.

Monica [59]

Action-reaction forces act on different objects; balanced forces act on the same object. Balanced forces can result in acceleration, action-reaction forces cannot. ... Newton's Third Law of Motion does not apply to balanced forces.

5 0

3 years ago