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Inessa05 [86]
2 years ago
13

A figure skater glides along a circular path of radius 6.70 m. If she coasts around one half of the circle, find the following.

Physics
1 answer:
adoni [48]2 years ago
8 0

(a) Her distance from the starting location is 21.05 m.

(b) The length of the path she skated is 21.05 m.

<h3>Distance of the skater from the starting position</h3>

The distance around a complete circular path is calculated as 2πr.

The distance for a half circle is calculated as ¹/₂ x 2πr = πr

Distance from the starting location = π x 6.7 m = 21.05 m

The length of the path she skated is the same as her distance from the starting location = 21.05 m.

Learn more about distance round a circle here: brainly.com/question/3100527

#SPJ1

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A motorcycle travels 90.0 km/h. How many seconds will it take the motorcycle to cover 2.10 x 103 m?
mina [271]

Answer:

The time taken is 84 seconds, please give the brainliest award would be much appreciated.

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5. It is the year 2085, and the world population has grown at an alarming rate. As a space explorer, you have been sent on a ter
shtirl [24]

Answer:

Answer:

It has sunlight, oxygen, water, and fertile soil.

Explanation:

Sunlight: provides plants (producers) with energy so that the ecosystem is sustainable. Also provides heat and warmth so the planet does not freeze.  

Oxygen: obvious. required for human survival and survival of most carbon-based organisms.

Water: required for plant growth and sustainability of carbon-based life.

Fertile soil: a place where plants can grow and produce energy.

I will not write an entire description because your teacher may accuse you of plagiarism and use this topic as proof.

Explanation:

3 0
3 years ago
Read 2 more answers
3 a A motorcyclist starts from rest and reaches
andrew-mc [135]

The acceleration of the body is 2 m/s^2 while the deceleration is - 1.2 m/s^2.

<h3>What is the acceleration?</h3>

Let us recall that the acceleration is the change in the speed of a body with time. We have been told that the body accelerates for 3s and then decelerates to 2s. This implies that the total time that the object spent in motion is 5 s.

Thus;

v = u + at

v = final velocity

u = initial velocity

a = acceleration

t = time taken

v - u/t = a

a = 6 - 0/3

= 2 m/s^2

Again;

v - u/t = a

a = 0 - 6/5

a = - 1.2m/s^2

Learn more about acceleration:brainly.com/question/12550364

#SPJ1

<h3 />
7 0
1 year ago
How much potential energy does a 1kg mess have 10m off the ground?
777dan777 [17]
Potential Energy = mass x gravitational acceleration x height
potential Energy = 1 x 9.8 x 10 = 98 joules
3 0
3 years ago
You are watching an archery tournament when you start wondering how fast an arrow is shot from the bow. Remembering your physics
spayn [35]

Answer:

v_0 = 3.53~{\rm m/s}

Explanation:

This is a projectile motion problem. We will first separate the motion into x- and y-components, apply the equations of kinematics separately, then we will combine them to find the initial velocity.

The initial velocity is in the x-direction, and there is no acceleration in the x-direction.

On the other hand, there no initial velocity in the y-component, so the arrow is basically in free-fall.

Applying the equations of kinematics in the x-direction gives

x - x_0 = v_{x_0} t + \frac{1}{2}a_x t^2\\63 \times 10^{-3} = v_0t + 0\\t = \frac{63\times 10^{-3}}{v_0}

For the y-direction gives

v_y = v_{y_0} + a_y t\\v_y = 0 -9.8t\\v_y = -9.8t

Combining both equation yields the y_component of the final velocity

v_y = -9.8(\frac{63\times 10^{-3}}{v_0}) = -\frac{0.61}{v_0}

Since we know the angle between the x- and y-components of the final velocity, which is 180° - 2.8° = 177.2°, we can calculate the initial velocity.

\tan(\theta) = \frac{v_y}{v_x}\\\tan(177.2^\circ) = -0.0489 = \frac{v_y}{v_0} = \frac{-0.61/v_0}{v_0} = -\frac{0.61}{v_0^2}\\v_0 = 3.53~{\rm m/s}

6 0
3 years ago
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