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2 years ago

A figure skater glides along a circular path of radius 6.70 m. If she coasts around one half of the circle, find the following.

Physics

1 answer:

adoni [48]2 years ago

8 0

(a) Her distance from the starting location is 21.05 m.

(b) The length of the path she skated is 21.05 m.

<h3>Distance of the skater from the starting position</h3>

The distance around a complete circular path is calculated as 2πr.

The distance for a half circle is calculated as ¹/₂ x 2πr = πr

Distance from the starting location = π x 6.7 m = 21.05 m

The length of the path she skated is the same as her distance from the starting location = 21.05 m.

Learn more about distance round a circle here: brainly.com/question/3100527

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The amount of energy lost at the transition between each trophic level of the pyramid of energy is about _______. a. 10% b. 50%

Sophie [7]

The amount of energy lost at the transition between each trophic level of the pyramid of energy is about 90%.

There are a total of 4 trophic levels.

The producers which bare plants represent the first trophic level. Herbivores represent the second trophic level. Carnivores represent the third trophic level. Top carnivores represent the fourth trophic level.

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1 year ago

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The type of transformer that is found outside a residential house is :
step-down transformer
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3 years ago

An elephant's legs have a reasonably uniform cross section from top to bottom, and they are quite long, pivoting high on the ani

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Answer:

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3 years ago

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The answer is B. Bye because B those study speed.

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A toy gun uses a spring to project a 4.5-g soft rubber sphere horizontally. The spring constant is 8.0 N/m, the barrel of the gu

marishachu [46]

Answer:

1.93 m/s

Explanation:

Parameters given:

Mass = 4.5g = 0.0045kg

Spring constant = 8.0 N/m

Length of barrel = 13 cm = 0.013m

Frictional force = 0.035N

Compression = 5.8 cm = 0.058m

First, we find the P. E. stored in the spring:

P. E. = ½*k*x²

P. E. = ½ * 8 * 0.058² = 0.013J

Then, we find the work done by the frictional force while the sphere is leaving the barrel of the gun:

Work = Force * distance

The distance here is the length of the barrel.

Work = 0.035 * 0.13 = 0.0046 J

The kinetic energy of the sphere can now be found:

K. E. = P. E. - Work done

K. E. = 0.013 - 0.0046 = 0.0084J

We can now find the speed using the formula for K. E.:

K. E. = ½*m*v²

0.0084 = ½ * 0.0045 * v²

v² = 0.0084/0.00255 = 3.733

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3 years ago

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