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3 years ago

15

PLEASE HELP HONESTLY!!! 50 POINTS TO THE BRAINIEST!!! :)

2 answers:

krek1111 [17]3 years ago

5 0

Im not gonna write for you a whole short story (I don't have time), but just describe what you observed (in a fake reality).

For the relationship between the predator-prey: you could say a snake eating a mouse.

Commenalism: lets say...moss grows on a tree and benefits, but it doesn't hurt or effect the tree.

Mutalism: a bird on a rhino. The bird eats parasites and bugs that feed off the rhino, the bird gets food and the rhino stays clean and parasite free.

Parasitism: a dog and a flea. Only the flea benefits from the dog. The dog has to suffer from the parasites evilness.

Now just thread it together and describe it. Comparing is easy, just use the definition of, for example, commensalism, mutalism, in one relationship, one organism benefits, in the other, both benefit.
Have fun!

dusya [7]3 years ago

4 0

I can do this for you tomorrow but you have to pm me. ILL have it done by tomorrow pm me for it and ill give it to you.

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a cylinder has a radius of 2.1cm and a length of 8.8cm .total charge 6.1 x 10^-7C is distributed uniformly throughout. the volum

7nadin3 [17]

The answer for the following problem is explained below.

Therefore the volume charge density of a substance (ρ) is 0.04 × $10^{-1}$ C.

Explanation:

Given:

radius (r) =2.1 cm = 2.1 × $10^{-2}$ m

height (h) =8.8 cm = 8.8 × $10^{-2}$ m

total charge (q) =6.1× $10^{-7}$ C

To solve:

volume charge density (ρ)

We know;

<u> ρ =q ÷ v</u>

volume of cylinder = π ×r × r × h

volume of cylinder =3.14 × 2.1 × 2.1 × $10^{-4}$ × 8.8 × $10^{-2}$

volume of cylinder (v) = 122.23 × $10^{-6}$

<u> ρ =q ÷ v</u>

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3 years ago

Which of the physical variables listed below will change when you change the area of the capacitor plates (while keeping the bat

RSB [31]

Answer:

a. Capacitance

b. Charge on the plates

e. Energy stored in the capacitor

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The capacitance of a capacitor is given as;

$C = \frac{Q}{V} = \frac{\epsilon _0 A}{d} \\\\$

where;

V is the potential difference between the plates

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$Q = \frac{V\epsilon _0 A}{d}$

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$E = \frac{1}{2} CV^2\\\\E = \frac{1}{2} (\frac{\epsilon _0 A}{d} )V^2$

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a. Capacitance

b. Charge on the plates

e. Energy stored in the capacitor

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