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Vladimir79 [104]
3 years ago
12

What forces are acting on a dropped book that falls to the floor?

Physics
1 answer:
pav-90 [236]3 years ago
5 0

Answer:

i believe its gravity

Explanation:

when something falls it is gravity doing its job

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The distance versus this plot for a particular object shows a quadratic relationship. Which column of distance data is possible
SOVA2 [1]

Answer:

A

Explanation:

In Column A, the pattern is 1², 2², 3², etc.  So x(t) = t², which is quadratic.

In Column B, the pattern is 2*1, 2*2, 2*3, etc.  So x(t) = 2t, which is linear.

In Column C, the pattern is 9*1, 9*2, 9*3, etc.  So x(t) = 9t, which is linear.

In Column D, the pattern is 1/1, 1/2, 1/3, etc.  So x(t) = 1/t, which is reciprocal.

In Column E, the pattern is 1/1², 1/2², 1/3², etc.  So x(t) = 1/t², which is reciprocal.

5 0
3 years ago
Two loudspeakers placed 8.0 m apart are driven in phase by an audio oscillator whose frequency range is 2.2 kHz to 2.9 kHz. A po
My name is Ann [436]

Answer:

The answer to the question is 2.2khz

Explanation:

<em>Let z₁ = 5.4m</em>

<em>Let z₂ = 4.6m</em>

<em>The path difference Δz = z₁-z₂ = 5.4 - 4.6 = 0.8m</em>

<em>For the interference= Δz λ, 2λ, 3λ......</em>

<em>The wavelength λ = 0.8m</em>

<em>The speed of sound v = 344m/s</em>

<em>The frequency f = v/λ = 344/0.8 = 430hz</em>

<em>Now,</em>

<em>f₁ =f, f₂= 2f, f₃ = 3f, f₄= 4f, f₅ =5f which is,</em>

<em>f₁ =f = 430Hz, f₂=2f =860Hz, f₃ =3f =1290Hz f₄ =4f =1720Hz and f₅=5f =2150Hz</em>

<em>f5 = 2120Hz = 2.200Hz </em>

<em>we will convert to two significant figures =2.2kHz</em>

<em> </em>

8 0
3 years ago
Chen is testing the friction of three surfaces. He pushes the same ball across three different surfaces with the same force and
Law Incorporation [45]

Answer:

im no proffesional

Explanation:

but i tghink you need a proffessional for this one

4 0
3 years ago
Page 40-44 earth science regents<br> just post the picture of the pages please
Anna007 [38]
I don’t know what book you’re talking about so I can’t help but have a look online, you may be able to find it if you search up the book name and look around a few websites
8 0
3 years ago
Calculate the elastic potential energy stored in a spring if it has a force constant of 150 N/m. the spring is extended to a len
Alenkinab [10]

Answer:

6.75J

Explanation:

U=1/2KΔx²

U=0.5* 150*0.30^2

4 0
2 years ago
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