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3 years ago

Plss help

Physics

1 answer:

Genrish500 [490]3 years ago

3 0

Answer:

Explanation:

imagine urself on an elevator dont you feel lighter

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A rock is dropped from a height of 3,245 m. If we ignore air resistance, how fast will it be travelling after it falls for 3.4 s

Marta_Voda [28]

Answer:

Explanation:

For a free falling object,it has constant acceleration and a changing velocity.

By using the velocity-time formula, the velocity can be obtained.

The height the rock travelled is the distance.

From,

Velocity (v) = Distance (d) / Time(t)

v = 3245m/3.4s

v = <u>954.4m/s</u>

That js the answer I got. Hope it's right.

3 0

3 years ago

A current of 2 A flows through a resistor. The voltage across the resistor is 18 V.

stepan [7]

Answer:

$R=9\ \Omega$

Explanation:

Given that,

Current, I = 2 A

Voltage across the resistor, V = 18 V

We need to find the value of resistance of the resistor. Let the resistance be R. We can find it using Ohm's law i.e.

V = IR

Where

R is the resistance of the resistor

$R=\dfrac{V}{I}\\\\R=\dfrac{18}{2}\\\\R=9\ \Omega$

So, the resistance of the resistor is equal to $9\ \Omega$ .

3 0

3 years ago

Finish the sentence

Amiraneli [1.4K]

Answer:

1. Equal and opposite reaction

2. Pairs

3. That is equal

Explanation:

I have tried my best but without knowing your curriculum or the possible answers it is difficult to know exactly what the answer would be... :(

Please mark as branliest ;)

- Hope this helped!

3 0

3 years ago

You are at the controls of a particle accelerator, sending a beam of 2.10×107 m/s protons (mass m) at a gas target of an unknown

Kipish [7]

Answer:

The mass is $m_2 =21.75*10^{-27} \ kg$

The velocity is $v_2 = 3.0*10^{6} m/s$

Explanation:

From the question we are told that

The speed of the protons is $u_1 = 2.10*10^{7} m/s$

The mass of the protons is $m$

The speed of the rebounding protons are $v_1 = -1.80 * 10^{7} \ m/s$

The negative sign shows that it is moving in the opposite direction

Now according to the law of energy conservation mass of one nucleus of the unknown element. is mathematically represented as

$m_2 = [\frac{u_1 -v_1}{u_1 + v_1} ] m_1$

Where $m_1$ is the mass of a single proton

So substituting values

$m_2 = \frac{2.10 *10^{7} - (-1.80 *10^{7})} {(2.10 *10^7) + (-1.80 *10^{7})} m_1$

$m_2 =13 m_1$

The mass of on proton is $m_1 = 1.673 * 10^{-27} \ kg$

So $m_2 =13 ( 1.673 * 10^{-27} )$

$m_2 =21.75*10^{-27} \ kg$

Now according to the law of linear momentum conservation the speed of the unknown nucleus immediately after such a collision is mathematically evaluated as

$m_1 u_1 + m_2u_2 = m_1 v_1 + m_2v_2$

Now $u_2$ because before collision the the nucleus was at rest

$m_1 u_1 = m_1 v_1 + m_2v_2$

=> $v_2 = \frac{m_1(u_1 -v_1)}{m_2}$

Recall that $m_2 =13 m_1$

$v_2 = \frac{m_1(u_1 -v_1)}{13m_1}$

=> $v_2 = \frac{(u_1 -v_1)}{13}$

substituting values

$v_2 = \frac{( 2.10*10^{7} -(-1.80 *10^{7}))}{13}$

$v_2 = 3.0*10^{6} m/s$

7 0

3 years ago

Will mark as brailiest if correct!!!!!!!!!

ivolga24 [154]

Answer:

D.diamond

Explanation:

Refraction occurs due to the bending of light rays as they pass from one medium to another. The light rays bend as their speed changes as they pass from one medium to another. The more the speed changes, the more the light bends and therefore more refraction occurs. When light passes from air to the diamond, the speed of light decreases more than any of the other materials listed in the given choices. So the light rays slow down the most diamond and so most refraction occurs in diamond.

5 0

3 years ago