I learned this one in Middle School too
<em /><u>B</u><u />aby <u>G</u><u />odzilla <u>E</u>ats <u>H</u>otdogs, <u>N</u><u />ot <u>C</u><u />occa <u>P</u><u />uffs
<u>B</u>elize <u>G</u><u />uatemala <u>E</u><u />l <u /><u />Salvador <u>H</u><u />onduras <u>N</u><u />icaragua <u>C</u><u />osta R<u />ica <u>P</u><u />anama
I hope I helped
ΩΩΩΩΩΩΩΩΩΩ
Answer:
B. v = λ X f
<em><u>Hope this helps! </u></em>
Answer:
14.04 m/s
Explanation:
To find the velocity of the first car after the collision, we can use the equation of conservation of momentum:
m1v1 + m2v2 = m1'v1' + m2'v2'
We have the following data:
m1 = m1' = 328,
m2 = m2' = 790,
v1 = 19.1,
v2 = 13,
v2' = 15.1.
Using this data, we can find v1' (final velocity of the first car):
328 * 19.1 + 790 * 13 = 328 * v1' + 790 * 15.1
16534.8 = 328 * v1' + 11929
328 * v1' = 4605.8
v1' = 14.04 m/s
Answer:
position 2
Explanation:
the gravity from the ball to the floor had the most movement involved.
Answer:
<h3>
30.66m</h3>
Explanation:
Using the equation of motion formula 
where;
S is the height to which the ball rises
u is the initial velocity of the ball = 0m/s
a is the acceleration due to gravity = 9.81m/s²
t is the time taken by the ball in air = 5.0s
Note that the time to rise to the peak is one-half the total hang-time = 5.0/2 = 2.5s
Substituting the given parameters into the formula above to get S:
This means that the ball rises 30.66m before it reaches its peak.
