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pochemuha
4 years ago
15

Predict the molecular shape of methane. trigonal pyramidal bent linear tetrahedral trigonal planar (120°) Predict the molecular

shape of the carbonate ion. tetrahedral linear trigonal pyramidal bent trigonal planar (120°) Predict the molecular shape of carbon dioxide. trigonal pyramidal linear trigonal planar (120°) tetrahedral bent Predict the molecular shape of the sulfite ion. trigonal planar (120°) linear bent trigonal pyramidal tetrahedral
Chemistry
1 answer:
Arisa [49]4 years ago
6 0

Answer:

Methane- tetrahedral

Carbonate ion- trigonal planar

CarbonIV oxide- Linear

Sulphite ion-tetrahedral

Explanation:

The shape of an ion according to VSEPR theory depends on the number of electron pairs present on the outermost shell of the central atom.

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Answer:

Q = 1267720 J

Explanation:

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∴ QH2O = mCpΔT

∴ m H2O = 500 g

∴ Cp H2O = 4.186 J/g°C = 4.183 E-3 KJ/g°C

∴ ΔT = 120 - 50 = 70°C

⇒ QH2O = (500 g)(4.183 E-3 KJ/g°C)(70°C) = 146.51 KJ

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moles H2O:

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How many molecules of CaCl2 are equivalent to 75.9 g CaCl2
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First, you need to find:
One mole of CaCl_{2} is equivalent to how many grams?

Well, for this you have to look up the periodic table. According to the periodic table:
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The atomic mass of <span>Chlorine Cl = 35.45 g (See in group 17)
</span>
As there are two atoms of Chlorine present in CaCl_{2}, therefore, the atomic mass of CaCl_{2} would be:

Atomic mass of CaCl_{2}  = Atomic mass of Ca + 2 * Atomic mass of Cl

Atomic mass of CaCl_{2} = 40.078 + 2 * 35.45 = 110.978 g

Now,

110.978 g of CaCl_{2} = 1 mole.
75.9 g of CaCl_{2} = \frac{75.9}{110.978} moles = 0.6839 moles.

Hence,
The total number of moles in 75.9g of CaCl_{2} = 0.6839 moles

According to <span>Avogadro's number,
1 mole = 1 * </span>6.022 * 10^{23} molecules
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Ans: Number of molecules in 75.9g of  CaCl_{2} =  4.118*10^{23} molecules

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