Since the half-reaction is occurring in a basic solution, add 32OH− to each side of the equation to eliminate the H+ ions.
P₄ +16H₂O + 32OH⁻ ⟶ 4PO₃⁻⁴ + 32H⁺ +32OH⁻
Final reaction :
P₄ + 32OH⁻ ⟶ 4PO₃⁻⁴ + 16H₂O + 20e⁻
A half reaction is either the oxidation or reduction reaction component of a redox reaction. A half reaction is obtained by considering the change in oxidation states of individual substances involved in the redox reaction.
The concept of half-reactions is used to describe what occurs in an electrochemical cell, such as a Galvanic cell battery. Half-reactions can be written to describe both the metal undergoing oxidation (known as the anode) and the metal undergoing reduction (known as the cathode).
Half-reactions are often used as a method of balancing redox reactions. For oxidation-reduction reactions in acidic conditions, after balancing the atoms and oxidation numbers, one will need to add H+ ions to balance the hydrogen ions in the half reaction.
For oxidation-reduction reactions in basic conditions, after balancing the atoms and oxidation numbers, first treat it as an acidic solution and then add OH- ions to balance the H+ ions in the half reactions (which would give H2O).
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The correct answer for the given question above would be option A. The compound that would most likely be found in a deposit of natural gas is CH4 or METHANE. Methane is the main constituent of natural gas. It is<span> a colorless, odorless gas with a wide distribution in nature. Hope this answers your question.</span>
Puede tomar los valores enteros positivos: n= 1, 2, 3, 4, 5, 6, 7. Por ejemplo si tengo un elemento químico que su último nivel es el 3s, su número cuántico principal sería el 3. Si tengo un elemento químico en que su último nivel es el 1s, entonces su número cuántico principal sería 1.
It would be a chem. reaction
Answer:
In solving this question it is important to note that entropy is referred to as the degree of randomness in a compound or system.
Entropy is highest in gas and lowest in solids
The order is given as:
Gas > Liquid > Solid
Another criteria is the more the elements in a compound, the more the entropy.
For example: KO3 has more entropy than KO2 due to the presence of more elements.
The last criteria is calculating their masses , the one with a greater mass has the higher entropy.
The option with the least entropy will be a solid. Al(s) and NaF(s) are both solids. NaF(s) has more elements in a compound which makes it have a higher entropy than Al(s). This means NaF(s) > Al(s).
The next to consider are the gaseous compounds which are HF(g) , SiF4(g) and SiH4(g). The least entropy will be HF(g) . This is because it has the least number of elements of the 3 compounds.
SiF4(g) and SiH4(g) have equal number of elements in a compound but the one with the highest mass is SiF4(g) because fluorine has a higher mass when compared to hydrogen. This means the compound with the highest entropy is SiF4(g).
The order of increasing entropy is given below:
Al(s) < NaF(s) < HF(g) < SiH4(g) < SiF4(g)
