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Musya8 [376]
3 years ago
11

What is (1.2 x 10^6 m) x ( 1.5 x 10^-7m) in scientific notation

Chemistry
1 answer:
Blababa [14]3 years ago
4 0

Answer:

4.875 × 105

(scientific notation)

= 4.875e5

(scientific e notation)

= 487.5 × 103

(engineering notation)

(thousand; prefix kilo- (k))

Explanation:

This all the ways

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Is the modern periodic table arranged based on atomic mass? <br> HELPP ILL GIVE BRAINLIEST
yan [13]

Answer: its b

Explanation:

4 0
3 years ago
Cis-platin is a chlorine-containing chemotherapy agent with the formula pt(nh3)2cl2. What is the mass of one mole of cis-platin?
marishachu [46]

Cis-platin is a chemotherapy agent used to treat and kill cancerous cells in patients. One mole of cis-platin has a mass of 300.06 grams/mol. Thus, option B is correct.

<h3>What is a chemotherapy agent?</h3>

A chemotherapy agent is an alkylating agent that is used to treat cancer and is given to reduce the infection or to relieve the symptoms. Cis-platin (Pt(NH₃)₂Cl₂) is one of the chemotherapy agents that treat lung, ovarian, and neck cancer, etc.

The mass of one mole of Cis-platin is calculated as,

Moles = mass ÷ molar mass

Where,

Moles = 1 mole

The molar mass of (Pt(NH₃)₂Cl₂) is calculated as,

195.06 g/mole + 2(17g/mole) + (35.5)2 = 300.06 grams

Substituting values to calculate mass:

Mass = Molar mass × moles

= 300. 06  × 1

= 300.06 grams/mol

Therefore, option B. 300.06 gm/mol is the mass of Cis-platin.

Learn more about chemotherapy agents here:

brainly.com/question/14260402

#SPJ4

Your question is incomplete, but most probably your full question was, Cis-platin is a chlorine-containing chemotherapy agent with the formula pt(nh3)2cl2. What is the mass of one mole of cis-platin?

  • 488.91 g/mol
  • 300.06 g/mol
  • 492.37 g/mol
  • 283.02 g/mol
  • 2860.5 g/mol
8 0
2 years ago
when 6.0 mol of oxygen are confined in a 36L vessel at 196°c, the pressure is 8atm. what is the new pressure for oxygen expands
kykrilka [37]

<u>Answer:</u> The new pressure for oxygen gas is 6 atm.

<u>Explanation:</u>

To calculate the new pressure of the gas, we use the equation given by Boyle's Law.

This law states that the pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

Mathematically,

P\propto \frac{1}{V}

or,

P_1V_1=P_2V_2

where,

P_1\text{ and }V_1 are the initial pressure and volume of the gas.

P_2\text{ and }V_2 are the final pressure and volume of the gas.

We are given:

P_1=8atm\\V_1=36L\\P_2=?atm\\V_2=48L

Putting values in above equation, we get:

8atm\times 36L=P_2\times 48L\\\\P_2=6atm

Hence, the new pressure for oxygen gas is 6 atm.

8 0
2 years ago
Select the correct answer.
marissa [1.9K]

Answer:

How does the equilibrium change with the removal of hydrogen (H2) gas from this equation? 2H2S ⇌ 2H2(g) + S2(g) A. ... Equilibrium shifts left to produce less reactant.

Explanation:

option A is the correct answer

Equilibrium shifts right to produce more product.

I hope it will help you.

3 0
2 years ago
If you combine neon argon and helium what would happen
Savatey [412]
All are gases so no visible reaction persay, unless in closed quarters and then massive pressure.
5 0
2 years ago
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