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inysia [295]
3 years ago
15

There are several ways to model a compound. One type of model is shown.

Chemistry
2 answers:
yawa3891 [41]3 years ago
8 0

Answer: The chemical formula for the formula given in the image is C_4H_9O_2.

Explanation: There are many ways in which a model can be represented:

  1. Molecular Formula
  2. Ball and Stick formula
  3. Expanded Formula
  4. Condensed Formula
  5. Skeletal Formula

This molecule is represented by the Expanded Structural Formula and by seeing in the image we can count the number of each element present.

Number of Carbon atoms present = 4

Number of Hydrogen atom present = 9

Number of Oxygen atom present = 2

Correct representation for this will be C_4H_9O_2.

allochka39001 [22]3 years ago
7 0

Answer:

The answer is D

Explanation:

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a 50.00-mL sample of bleach solution contains 0.214 M HClO and 0.667 M NaClO. The Ka of hypochlorous acid is 3.0 ✕ 10−8. Find th
amm1812

Answer:

A) pH = 8.11

B) pH = 7.96

Explanation:

The pH of buffer is calculated using Henderson Hassalbalch's equatio, which is

pH=pKa+log\frac{[salt]}{[acid]}

pKa = -logKa = -log(3.0 ✕ 10⁻⁸)

pKa = 7.5

[salt] = 0.667

[Acid] = 0.214

pH = 7.5 + log\frac{0.667}{0.214}=7.99

A) If the solution is halved it means the concentration of both salt and acid will be the same.

The volume will change

Number of moles of acid = molarity X volume = 0.214 X 25 = 5.35 mmol

Number of moles of salt = molarity X volume = 0.667 X 25 = 16.68 mmol

moles of NaOH added = molarity X volume = 0.100 X 10 = 1 mmol

These moles of NaOH will react with acid to give same amount of salt and thus the moles of acid will decrease

New moles of acid = 5.35 - 1 = 4.35

New moles of salt = 16.68 + 1 = 17.68

the new pH will be

pH = 7.5 + log\frac{17.68}{4.35}=8.11

B)

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These moles of HCl will react with salt to give same amount of acid and thus the moles of salt will decrease

New moles of acid = 5.35  + 1 = 6.35

New moles of salt = 16.68 - 1 = 15.68

the new pH will be

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A water molecule, because of its shape, is a polar molecule.
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POH will be -log[conc of OH]
-log (3.9E-08) = 7.409
pH = 14- pOH
pH = 14 - 7.409
pH = 6.59
3 0
4 years ago
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