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cupoosta [38]
3 years ago
15

hat is the product when magnesium reacts with nitrogen? Mg(s) + N2(g) → Mg2N3(s) Mg3N(s) Mg3N2(s) MgN3(s)

Chemistry
2 answers:
Ipatiy [6.2K]3 years ago
5 0
3Mg + N₂ = Mg₃N₂

Mg₃N₂
______________________
Pani-rosa [81]3 years ago
5 0

<u>Answer:</u> The product of the given reaction is Mg_3N_2(s)

<u>Explanation:</u>

When magnesium solid reacts with nitrogen gas, it leads to the formation of an ionic solid known as magnesium nitride.

The chemical equation for the reaction of magnesium and nitrogen gas follows:

3Mg(s)+N_2(g)\rightarrow Mg_3N_2(s)

By Stoichiometry of the reaction:

3 moles of magnesium solid reacts with 1 mole of nitrogen gas to produce 1 mole of magnesium nitride.

The given reaction is considered as synthesis reaction.

Hence, the product of the given reaction is Mg_3N_2(s)

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Answer:

24.6 g

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a concentration solution of H2so4 is 59.4% by mass (m/m) and has a density of 1.83 g/mL. How many mL of the solution would be re
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Answer: 41.5 mL

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n}{V_s}

where,

n = moles of solute

V_s = volume of solution in L

Given : 59.4 g of H_2SO_4 in 100 g of solution  

moles of H_2SO_4=\frac{\text {given mass}}{\text {molar mass}}=\frac{59.4g}{98g/mol}=0.61

Volume of solution =\frac{\text {mass of solution}}{\text {density of solution}}=\frac{100g}{1.83g/ml}=54.6ml

Now put all the given values in the formula of molality, we get

Molality=\frac{0.61\times 1000}{54.6ml}=11.2M

To calculate the volume of acid, we use the equation given by neutralisation reaction:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of stock acid which is H_2SO_4

M_2\text{ and }V_2 are the molarity and volume of dilute acid which is H_2SO_4

We are given:

M_1=11.2M\\V_1=mL\\M_2=0.30M\\V_2=1550mL

Putting values in above equation, we get:

11.2\times V_1=0.30\times 1550\\\\V_1=41.5mL

Thus 41.5 mL of the solution would be required to prepare 1550 mL of a .30M solution of the acid

4 0
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<u>Explanation:</u>

Valence electrons are defined as the electrons which are present in outer most orbital of an atom.

Sulfur is the 16th element of the periodic table having 16 electrons.

Electronic configuration of sulfur atom is 1s^22s^22p^63s^23p^4

The number of valence electrons are 2 + 4 = 6

These 6 electrons enter s-orbital and p-orbital but the outermost valence electron will enter the p-orbital.

Hence, the outermost valence electron enters p orbital.

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Answer:

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