Question

Please help me answer this chemistry problem!

Answer 1

For the first equation, we know that the Be gained a proton and became B. In order to cancel this out, we would need a $\frac{0}{-1} \beta$ particle. This particle is also called a beta particle.

For the second equation, we know that Si gained a proton and became P. The particle for this equation would also be a beta particle ($\frac{0}{-1} \beta$), as the same thing is happening as in the first equation.

For the third equation, we know that some atom plus an alpha particle gives us platinum-192. By subtracting the 4 and 2 from the alpha particle, we get the missing atom to be $\frac{188}{76} Os$, or osmium-188.

For the last equation, we can simply add the mathematical value of the beta particle to the aluminum-28. This gives us a changed proton number, but not atomic mass with the missing atom being $\frac{28}{12} Mg$, or magnesium-28.

Hope this helps!