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3 years ago

At which point or points does the pendulum have the greatest kinetic energy?

Physics

2 answers:

deff fn [24]3 years ago

5 0

Answer:

At the bottom.

Explanation:

A pendulum possess two types of energies i.e. kinetic energy and potential energy. We know that a pendulum oscillates about its mean position. At both extreme points, it have zero kinetic energy and maximum potential energy. As it swings down, its potential energy gets converted to the kinetic energy.

As a result, it have zero potential energy and maximum kinetic energy at the bottom point. Hence, the pendulum have the greatest kinetic energy at the bottom.

Daniel [21]3 years ago

4 0

At the lowest point of its motion, kinetic energy is maximum and potential energy is minimum. This is where the velocity is a maximum. At the highest point of its motion, kinetic energy is minimum (i.e. zero) and potential energy is maximum.

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A bead slides without friction around a loopthe-loop. The bead is released from a height 18.6 m from the bottom of the loop-the-

12345 [234]

Answer:

See explanation

Explanation:

To do this, you need to use energy conservation. The sum of kinetic and potential energies is the same at all points along the path so, you can write the expression like this:

1/2mv1² + mgh1 = (1/2)mv2² + mgh2

Where:

v1 = 0 because it's released from rest

h1 = 18.6 m

v2 = speed we want to solve.

h2 = height at point A. In this case, you are not providing the picture or data, so, I'm going to suppose a theorical data to solve this. Let's say h2 it's 12 m.

Now, let's replace the data in the above expression (assuming h2 = 12 m). Also, remember that we don't have the mass of the bead, but we don't need it to solve it, because it's simplified by the equation, therefore the final expression is:

1/2v1² + gh1 = 1/2v2² + gh2

Replacing the data we have:

1/2*(0) + 9.8*18.6 = 1/2v² + 9.8*12

182.28 = 117.6 + 1/2v²

182.28 - 117.6 = v²/2

64.68 * 2 = v²

v = √129.36

v = 11.37 m/s

Now, remember that you are not providing the picture to see exactly the value of height at point A. With that picture, just replace the value in this procedure, and you'll get an accurate result.

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3 years ago

HELP MEH I WILL BIVE BRAINLYEST !!

sdas [7]

Answer:

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Explanation:

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3 years ago

3rd newton law You step off a curb

Naddika [18.5K]

-- Your foot hits the street.

-- Your foot exerts a force down onto e pavement.

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1 year ago

PE=30J, m=?, g=10m/s2, h=10m

OleMash [197]

Based on the given, this is probably a gravitational potential energy problem (PEgrav). The formula for PEgrav is:

PEgrav = mgh

Where:
m = mass (kg)
g = acceleration due to gravity
h = height (m)

With this formula you can derive the formula for your unknown, which is mass. First put in what you know and then solve for what you do not know.

$PEgrav=mgh$
$30J=m(10)(10[tex] \frac{30}{100} =m$ )[/tex]

Do operations that you can with what is given first.

$30J=m(100m)$

Transpose the 100 to the other side of the equation. Do not forget that when you transpose, you do the opposite operation.

$\frac{30}{100} =m$

m = 0.30kg

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3 years ago

A light-rail commuter train speeds up at a rate of 1.65 m/s 2 and takes 19.0 s to reach its top speed. How far down the tracks d

Margarita [4]

Answer:

297.8 m

Explanation:

We are given that

Acceleration= $a=1.65m/s^2$