Answer:
The magnitude of force is 1.86 N and the direction of force is towards the other wire.
Explanation:
Given:
Current flowing through each power line, I = 130 A
Distance between the two power lines, d = 40 cm = 0.4 m
Length of power lines, L = 220 m
The force exerted by the power lines on each other is given by the relation:
Substitute the suitable values in the above equation.
F = 1.86 N
Since the direction of current flowing through the power lines are opposite to each other, so the force is attractive in nature. Hence, the direction of force experienced by the power lines on each other is towards the each other.
Well, there's a lot of friction going on there, so the snowball gradually
loses kinetic energy just from bouncing and plowing through the snow
on the ground.
But I don't think you're asking about that. I think you're ignoring that
for the moment, and asking how its kinetic energy changes as its
mass increases. We know that
Kinetic Energy = (1/2) (mass) (speed²)
and THAT seems to say that more mass means more kinetic energy.
So maybe the snowball's kinetic energy increases as it picks up
more mass.
Don't you believe it !
Remember: Energy always has to come from somewhere ... a motor,
a jet, a push, gravity ... something ! It doesn't just appear out of thin air.
If the snowball were rolling down hill, then it could get more kinetic energy
from gravity. But if it's rolling on level ground, then it can never have any
more kinetic energy than you gave it when you pushed it and let it go.
If snow or leaves stick to it and its mass increases, then its speed must
decrease, in order to keep the same kinetic energy.
Answer:
The right approach is "8.1 m/s". A further explanation is provided below.
Explanation:
According to the table,
Speed of Boat
=
Now,
⇒
or,
⇒
The student's vertical speed when he was thrown out = 14.14 m/s
Speed of the student if he hit the ground = 14.14 m/s
Explanation:
Step 1:
It is given that the student reached a maximum height of 10 meters when he was thrown out. The initial speed with which he was throw is to be estimated.
Step 2:
The equation of motion connecting initial velocity, final velocity and distance is where v is the final velocity, u is the velocity with which he was thrown, a is acceleration due to gravity and s is the height.
The final velocity at the highest point 10 meters will be 0
s = 10 m
a = -10 m/
0 = + 2*(-10)*10
u = = 14.14 m/s
Step 3:
The final speed when the student hits the ground will be the same as initial speed of the student when he was thrown out.
So the final speed of the student if he hit the ground would be 14.14 m/s
Step 4:
Answer:
The student's vertical speed when he was thrown out = 14.14 m/s
Speed of the student if he hit the ground = 14.14 m/s