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3 years ago

At which point or points does the pendulum have the greatest kinetic energy?

Physics

2 answers:

deff fn [24]3 years ago

5 0

Answer:

At the bottom.

Explanation:

A pendulum possess two types of energies i.e. kinetic energy and potential energy. We know that a pendulum oscillates about its mean position. At both extreme points, it have zero kinetic energy and maximum potential energy. As it swings down, its potential energy gets converted to the kinetic energy.

As a result, it have zero potential energy and maximum kinetic energy at the bottom point. Hence, the pendulum have the greatest kinetic energy at the bottom.

Daniel [21]3 years ago

4 0

At the lowest point of its motion, kinetic energy is maximum and potential energy is minimum. This is where the velocity is a maximum. At the highest point of its motion, kinetic energy is minimum (i.e. zero) and potential energy is maximum.

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A car turns from a road into a parking lot and into an available parking space. The car's initial velocity is 4 m/s [E 45° N]. T

melamori03 [73]

Answer:

Explanation:

From the given information:

The car's initial velocity = 4 m/s in the direction of east 45° due north

We can therefore express the vector of this component form as:

v₁ = (4 m/s) (cos(45º)i + sin(45º)j)

v₁ = (2.83 m/s)i + (2.83 m/s)j

Similarly, the car's final velocity = 4 m/s in the direction of the east side 10º north

∴

v₂ = (4 m/s) (cos(10º) i + sin(10º) j)

v₂ = (3.94 m/s) i + (0.695 m/s) j

From the first equation of motion

v = u + at

Making acceleration "a" the subject of the formula, we have:

a = (v - u )/t

a = (v₂ - v₁)/t

a = (0.370 m/s²) + (-0.711 m/s²)

The magnitude of the avg. acceleration is:

$|| a||= \sqrt{(0.370 m/s^2)^2 + (-0.711 m/s^2)^2)$

$|| a||= 0.8015 \ m/s^2$

And;

The direction can be determined by taking the tangent of the acceleration:

i.e.

$tan(\theta) = \dfrac{-0.711 m/s^2}{ 0.370 m/s^2}$

$tan(\theta) = -1.9216$

$\theta = tan^{-1} ( -1.9216 )$

$\mathbf{\theta = -62.51 ^0}$

Thus, the direction of the angle is approximately S 62.51º E

7 0

3 years ago

What is your average velocity if you drive a distance of 113 km at a speed of 47 km/h, then the same distance at a speed of 66 k

Sauron [17]

Answer:

$V_{avg}=54.90\ km/h$

Explanation:

Given that

Drive 113 km at 47 km/h and another 113 km at 66 km/h.

When distance is same then average velocity can be found by using below formula:

$V_{avg}=\dfrac{2V_1V_2}{V_1+V_2}$

Here

$V_1= 47\ km/h$

$V_2= 66\ km/h$

Now by putting the values

$V_{avg}=\dfrac{2V_1V_2}{V_1+V_2}$

$V_{avg}=\dfrac{2\times 47\times 66}{47+66}$

$V_{avg}=54.90\ km/h$

8 0

4 years ago

Read 2 more answers

Match each characteristic with the type of wave it corresponds to. Longitudinal waves Transverse waves The direction the wave tr

zubka84 [21]

Answer:The direction the wave travels is parallel to the displacement of the medium.LW.

Electromagnetic waves are an example of this type of wave. TW

Sound waves are an example of this type of wave.LW

Ir the wave propagates in the x‑direction, the medium is also disturbed in the x‑direction. LW

If the wave propagates in the x‑direction, the medium is disturbed in the y‑ and/or z‑direction. TW

The direction the wave travels is perpendicular to the displacement of the medium.TW

Explanación:

the main difference of Transversal AND Longitudinal waves (TW AND LW) is that the disturbation direction in the media with respect to the travel direction is well different for both cases. For TW the perturbation oscilatiew perpendicular to propagation direction of the wave.

In constrant for LW the disturbation oscilates in the same direction as the wave is propagating.

3 0

3 years ago

Read 2 more answers

Starting with the definition 1.00 in. = 2.54 cm, find the number of kilometers in 8.00 mi .

velikii [3]

Use Factor-Label Method:

8miles 63360 inches
---------- X --------------------- X
1 1 mile

2.54cm 1 meter
X ------------ X ---------------- X
1 inch 100 cm

1 km
----------------- = 12.87 km
1000meters

8 miles = 12.87 km

8 0

4 years ago

Which of the followings are true about Vmax? A. The higher the [enzyme], the higher the Vmax B. Vmax is proportional to k2 C. Vm

Vera_Pavlovna [14]

Answer:

Correct answer is A.

The higher the enzyme, the higher the Vmax

Explanation:

Although, in the absence of enzyme, the rate of a reaction(Vmax) increase linearly with substrate concentration. The reaction rate is given as dp/dt.

The rate of a reaction involving enzyme also increases.

At low enzyme concentrations or high substrate concentrations, all of the available enzyme active sites could be occupied with substrates. Therefore, increasing the substrate concentration further will not change the rate of diffusion. In other words, there is some maximum reaction rate (Vmax) when all enzyme active sites are occupied. The reaction rate will increase with increasing substrate concentration, but must asymptotically approach the saturation rate, Vmax. Vmax is directly proportional to the total enzyme concentration, E

5 0

3 years ago