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Pachacha [2.7K]
3 years ago
6

How many moles are in 98.3 grams of aluminum hydroxide, Al(OH)3?

Chemistry
1 answer:
Musya8 [376]3 years ago
6 0
We have to calculate the molar mass of  AL(OH)₃
Atomic mass (Al)=27 amu
Atomic mass (O)=16 amu
Atomic mass (H)=1 amu

molecular weight= 27 amu+3(16 amu + 1 amu) =78 amu.

Therefore, the molar mass of Al (OH)₃ is 78 g/ mol

Now, we calculate the number of moles in 98.3 g of aluminum hydroxide.

78 g-------------------1 mol
98.3 g-----------------  x

x=(98.3 g * 1 mol) / 78 g=1.26 moles.

Answer: 1.26 moles.
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Explanation:

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