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Pachacha [2.7K]
3 years ago
6

How many moles are in 98.3 grams of aluminum hydroxide, Al(OH)3?

Chemistry
1 answer:
Musya8 [376]3 years ago
6 0
We have to calculate the molar mass of  AL(OH)₃
Atomic mass (Al)=27 amu
Atomic mass (O)=16 amu
Atomic mass (H)=1 amu

molecular weight= 27 amu+3(16 amu + 1 amu) =78 amu.

Therefore, the molar mass of Al (OH)₃ is 78 g/ mol

Now, we calculate the number of moles in 98.3 g of aluminum hydroxide.

78 g-------------------1 mol
98.3 g-----------------  x

x=(98.3 g * 1 mol) / 78 g=1.26 moles.

Answer: 1.26 moles.
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Solution:-  We have been given with 6.0 moles of nitrous acid and asked to calculate it's grams. Moles to grams is a unit conversion and for doing this conversion we multiply the given moles by the molar mass of the compound.

Molar mass is the formula mass and to calculate this the atomic masses of each atom are multiplied by their respective subscripts that is the number of the atom in the compound .

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