Answer:
![v_f = v_i + at](https://tex.z-dn.net/?f=v_f%20%3D%20v_i%20%2B%20at)
![v_f = 13.23 m/s](https://tex.z-dn.net/?f=v_f%20%3D%2013.23%20m%2Fs)
Explanation:
Height Of the watermelon when it is dropped is given as
![h = 80 m](https://tex.z-dn.net/?f=h%20%3D%2080%20m)
time of fall under gravity
![t = 1.35 s](https://tex.z-dn.net/?f=t%20%3D%201.35%20s)
now if water melon start from rest then we have
![v_i = 0](https://tex.z-dn.net/?f=v_i%20%3D%200)
acceleration due to gravity for watermelon
![a = 9.81 m/s^2](https://tex.z-dn.net/?f=a%20%3D%209.81%20m%2Fs%5E2)
now we need to find the final speed of watermelon
![v_f = v_i + at](https://tex.z-dn.net/?f=v_f%20%3D%20v_i%20%2B%20at)
so we will have
![v_f = 0 + (9.81)(1.35)](https://tex.z-dn.net/?f=v_f%20%3D%200%20%2B%20%289.81%29%281.35%29)
![v_f = 13.23 m/s](https://tex.z-dn.net/?f=v_f%20%3D%2013.23%20m%2Fs)
Answer:
(a) The resistance R of the inductor is 2480.62 Ω
(b) The inductance L of the inductor is 1.67 H
Explanation:
Given;
emf of the battery, V = 16.0 V
current at 0.940 ms = 4.86 mA
after a long time, the current becomes 6.45 mA = maximum current
Part (a) The resistance R of the inductor
![R = \frac{V}{I_{max}} = \frac{16}{6.45*10^{-3}} = 2480.62 \ ohms](https://tex.z-dn.net/?f=R%20%3D%20%5Cfrac%7BV%7D%7BI_%7Bmax%7D%7D%20%3D%20%5Cfrac%7B16%7D%7B6.45%2A10%5E%7B-3%7D%7D%20%3D%202480.62%20%5C%20ohms)
Part (b) the inductance L of the inductor
![\frac{Rt}{L} = -ln(1-\frac{I}I_{max}})\\\\L = \frac{Rt}{-ln(1-\frac{I}I_{max})}}](https://tex.z-dn.net/?f=%5Cfrac%7BRt%7D%7BL%7D%20%3D%20-ln%281-%5Cfrac%7BI%7DI_%7Bmax%7D%7D%29%5C%5C%5C%5CL%20%3D%20%5Cfrac%7BRt%7D%7B-ln%281-%5Cfrac%7BI%7DI_%7Bmax%7D%29%7D%7D)
where;
L is the inductance
R is the resistance of the inductor
t is time
![L = \frac{Rt}{-ln(1-\frac{I}I_{max})}} = \frac{2480.62*0.94*10^{-3}}{-ln(1-\frac{4.86}{6.45})} \\\\L =\frac{2.3318}{1.4004} = 1.67 \ H](https://tex.z-dn.net/?f=L%20%3D%20%5Cfrac%7BRt%7D%7B-ln%281-%5Cfrac%7BI%7DI_%7Bmax%7D%29%7D%7D%20%3D%20%5Cfrac%7B2480.62%2A0.94%2A10%5E%7B-3%7D%7D%7B-ln%281-%5Cfrac%7B4.86%7D%7B6.45%7D%29%7D%20%5C%5C%5C%5CL%20%3D%5Cfrac%7B2.3318%7D%7B1.4004%7D%20%3D%201.67%20%5C%20H)
Therefore, the inductance is 1.67 H
were solving for v velocity of the ball after it has hit the bottle. a. momentum ->p=mv->ball + bottle momentum during hit = ball + bottle momentum after hit-> ball (.5*21)+ bottle (.2*0) (it's 0 because the the bottle is standing still) = ball after hit (.5*v)+bottle after hit (.2*30) -> 10.5+0=.5v+6 ->4.5=.5v->v=9m/s
b. if bottle was heavier the ball would be slower so final velocity would decrease
Answer:
Always wear safety goggles when performing an experiment.
Use caution when dropping objects and/or launching them into the air.
Use only the materials that your teacher provides or approves.
Check the soda bottle and its cap for cracks and chips prior to use.
Report all accidents—no matter how big or small—to your teacher.
In a problem where a child is danger form drowning from a river who has a current of 3.1km/hr to east and the child is 0.6km fro the shore and the upstream is 2,5km from the dock. So base on the question the boat with a speed of 24.8 km/hr is 1.9 km because the child is 0.6 km off the dock so 2.5 minus 0.6