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Sergio039 [100]
3 years ago
5

A car accelerates from rest to a velocity of 5 meters/second in 4 seconds. What is its average acceleration over this period of

time? A. Its acceleration is 1.25 meters/second. B. Its acceleration is 5 meters/second. C. Its acceleration is 0.8 meters/second. D. Its acceleration is 1.25 meters/second2. E. Its acceleration is 20 meters.
Physics
2 answers:
Natali5045456 [20]3 years ago
7 0

Answer:

The acceleration of the car is  a=1.25\ m/s^2.

Explanation:

It is given that,

Initial speed of the car, u = 0

Final speed of the car, v = 5 m/s

Time, t = 4 s

<em>We need to find the average acceleration over this period of time. It is given by the rate of change of velocity. It is given by :</em>

a=\dfrac{v-u}{t}

a=\dfrac{(5-0)\ m/s}{4\ s}

a=1.25\ m/s^2

So, the acceleration of the car is  a=1.25\ m/s^2. Hence, the correct option is (D).

disa [49]3 years ago
5 0

The average acceleration is

\bar a=\dfrac{5\,\frac{\mathrm m}{\mathrm s}-0\,\frac{\mathrm m}{\mathrm s}}{4\,\mathrm s}=1.25\,\dfrac{\mathrm m}{\mathrm s^2}

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m_1u_{1j}+m_2u_{2j}=m_1v_{1j}+m_2v_{2j}\\v_{2j} = \frac{m_1u_{1j}+m_2u_{2j}-m_1v_{1j}}{m_2}=\frac{(2\cdot 30+2\cdot5-2\cdot20)kg\frac{m}{s}}{2kg}=15\frac{m}{s}

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Refer to the sketch attached. The pendulum is initially at \rm P_2. Its highest point is at P_1. The length of segment \rm BP_2 gives the change in its height.

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