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Sergio039 [100]
3 years ago
5

A car accelerates from rest to a velocity of 5 meters/second in 4 seconds. What is its average acceleration over this period of

time? A. Its acceleration is 1.25 meters/second. B. Its acceleration is 5 meters/second. C. Its acceleration is 0.8 meters/second. D. Its acceleration is 1.25 meters/second2. E. Its acceleration is 20 meters.
Physics
2 answers:
Natali5045456 [20]3 years ago
7 0

Answer:

The acceleration of the car is  a=1.25\ m/s^2.

Explanation:

It is given that,

Initial speed of the car, u = 0

Final speed of the car, v = 5 m/s

Time, t = 4 s

<em>We need to find the average acceleration over this period of time. It is given by the rate of change of velocity. It is given by :</em>

a=\dfrac{v-u}{t}

a=\dfrac{(5-0)\ m/s}{4\ s}

a=1.25\ m/s^2

So, the acceleration of the car is  a=1.25\ m/s^2. Hence, the correct option is (D).

disa [49]3 years ago
5 0

The average acceleration is

\bar a=\dfrac{5\,\frac{\mathrm m}{\mathrm s}-0\,\frac{\mathrm m}{\mathrm s}}{4\,\mathrm s}=1.25\,\dfrac{\mathrm m}{\mathrm s^2}

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The angular speed is decreasing and direction of rotation clockwise of the rod immediately after time t.

<h3></h3><h3>What is angular speed ?</h3>

The rate of change of angular displacement is defined as angular speed.  It is stated as follows:

ω = θ t

Where,

θ is the angle of rotation,

t is the time

ω is the angular velocity

The torque is found as;l

\rm  T = F \times r

If the force is acting on the rod  from the three point is the same, the value of the torque is depends upon the radius or the perpendicular distance.

The perpendicular distance of the right force is grater. Hence, the force acting on the right side is more, and the rod will rotate clockwise.

Both the forces are acting downwards. Thus, the resultant force is the less due to which the speed is increasing.

Hence, the angular speed is decreasing and direction of rotation clockwise of the rod immediately after time t.

To learn more about the angular speed, refer to the link;

brainly.com/question/9684874

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5 0
2 years ago
What type of acceleration does an object moving in a circular path with constant speed experience?
Marysya12 [62]

An object moving in a circular path has centripetal acceleration. <em>(A)</em>

7 0
3 years ago
Read 2 more answers
A machinist with normal vision has a near point at 25 cm. The machinist wears eyeglasses in order to do close work. The power of
Alik [6]

Answer:

17.4 cm

Explanation:

Power of lens = +1.75 diopters

Focal length of lens

f=\frac{100}{1.75}=\frac{400}{7}

This is a convex lens as focal the diopter given is positive which makes the focal length positive. Image distance will be negative.

v = -25

\frac{1}{v}-\frac{1}{u}=\frac{1}{f}\\\Rightarrow \frac{1}{-25}-\frac{1}{u}=\frac{1}{\frac{400}{7}}\\\Rightarrow -\frac{1}{u}=\frac{7}{400}+\frac{1}{25}\\\Rightarrow \frac{1}{u}=-\frac{7}{400}-\frac{1}{25}\\\Rightarrow \frac{1}{u}=-0.0575\\\Rightarrow u=-17.4\ cm

∴ The new near point is 17.4 cm

7 0
3 years ago
An ice cube at 0c was dropped into 30.0 g of water in a cup at 45.0c. at the instant that all of the ice was melted, the tempera
Ede4ka [16]
The amount of heat given by the water to the block of ice can be calculated by using
Q=m_w C_{sw} \Delta T_w
where 
m_w = 30 g is the mass of the water
C_{sw}=4.18 J/(g ^{\circ}C) is the specific heat capacity of water
\Delta T_w = 45.0^{\circ}-19.5^{\circ}C = 20.5^{\circ}C is the variation of temperature of the water.

Using these numbers, we find
Q=(30 g)(4.18 J/(g^{\circ}C))(20.5^{\circ}C)=2571 J

This is the amount of heat released by the water, but this is exactly equal to the amount of heat absorbed by the ice, used to melt it into water according to the formula:
Q = m_i L_f
where m_i is the mass of the ice while L_f =334 J/g is the specific latent heat of fusion of the ice.
Re-arranging this formula and using the heat Q that we found previously, we can calculate the mass of the ice:
m_i =  \frac{Q}{L_f}= \frac{2571 J}{334 J/g} =7.7 g
3 0
3 years ago
The critical angle for water is 49°. If a ray of light
Sonja [21]

Answer:

Snell's Law states

Ni sin i = Nr sin r

Judging from the question the source of the ray is in the water (directed up)

or NI = 1 / sin 49      Ni = 1.325 deg     the critical angle

From inside the pond:

Nr = 1.325 * sin 45 / 1 = 94 deg  

So refraction can occur  outside the pond and you do not have total internal refection.

 

3 0
3 years ago
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