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Semenov [28]
3 years ago
5

HELP HELP HELP HOW MANY GRAMS OF SUGAR CAN DISSOLVE IN 100 GRAMS OF WATER HEATED TO 40 CELCIOUS 60 POINTS OFFERED

Chemistry
1 answer:
Colt1911 [192]3 years ago
3 0

your answer would be C. 240g

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PV = nRT. If P = 1 atm, V = 5.0 liter, R = 0.0821 L.atm/mol.K, and T = 293 K; what is the value of n?
Leya [2.2K]

Answer:

n = 0.207 mole

Explanation:

We have,

P = 1 atm

V = 5 liter

R = 0.0821 L.atm/mol.K

T = 293 K

We need to find the value of n. The relation is as follows :

PV = nRT

Solving for n,

n=\dfrac{PV}{RT}\\\\n=\dfrac{1\times 5}{0.0821 \times 293}\\\\n=0.207\ \text{mol}

So, the value of n is 0.207 mol.

6 0
3 years ago
A pharmacist has a 12% solution of boric acid and a 20% solution of boric acid. How much of each must he use to make 80 grams of
Iteru [2.4K]

Answer:

  • <u><em>He must use 50g of the 12% solution and 30 g of the 20% solution.</em></u>

<u><em></em></u>

Explanation:

Call x the amount of <em>12% boric acid </em>solution to be used.

  • The content of acid of that is: 0.12x

Since he wants to make <em>80 grams</em> of solution, the amount of <em>20% boric acid</em> solution to be used is 80 - x.

  • The content of acid of that is{ 0.20(80 - x).

The final solution is <em>15% </em>concentrated.

  • The content of boric acid of that is 0.15 × 80 g.

Now you have can write your equation:

         0.12x+0.20(80-x)=0.15\times 80

Solve:

           0.12x + 16 - 0.20x=12\\\\-0.08x=12-16\\\\0.08x=4\\\\x=4/0.08\\\\x=50

That is 50 grams of the 12% solution of boric acid.

Calculate the amount of the 20% solution of boric acid:

         80-x=80-50=30

That is 30 grams.

Then, he must use 50g of the 12% solution and 30 g of the 20% solution.

5 0
3 years ago
What type of compound is calcium oxide
DIA [1.3K]
A carbonate because the oxygen neutralizes the reactive coding of the calcium in its original form.
5 0
3 years ago
I have a brick, dimensions 4 cm tall, 9 cm wide, and 25 cm long, with a mass of 1250 g. What is the density?
Likurg_2 [28]

Answer:

1.389

Explanation:

P = m / V

m = 1250

V = 4x9x25 = 900

1250/900 = 1.388889

7 0
3 years ago
How do the metals in group 1 compare with the transition metals?
Nimfa-mama [501]

Answer:

Group 1 metals and transition metals are different from each other, mainly based on the colour of the chemical compounds that they form. The key difference between group 1 metals and transition metals is that the group 1 metals form colourless compounds, whereas the transition metals form colourful compounds.

6 0
3 years ago
Read 2 more answers
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