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sergejj [24]
3 years ago
7

Draw additional masses to show how the block can be made to move toward point A. Be sure to draw the string and label the mass o

f the block. For full credit, draw the minimum number of blocks required to make the block move toward point A.
Physics
1 answer:
jeyben [28]3 years ago
5 0
With 250 grams pullling to the right and 100 grams pulling towards A, you will have some movement towards the right and some movement towards A. The resultant vector will be angled between those two directions. 
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The volume of a cylindrical tin can with a top and a bottom is to be 16π cubic inches. If a minimum amount of tin is to be used
sergiy2304 [10]

Answer:

h = 4 in

Explanation:

GIVEN DATA:

volume of tin= 16 \pi

we know that

volume of cylinder is v = \pi r^2  h

so,

16 \pi = \pi r^2 h

16 = r^2 h

r = \sqrt{\frac{16}{h}}

construct formula for surface area

S = 2\pi r^2 +  2\pi rh

S = \frac{2v}{h} + 2 \sqrt{v \pi h}

minimize the function wrt  h

S' = \frac{2v}{h^2} + \sqrt{\frac{v \pi}{h} =  0

solving for h we have

h = [\frac{4 v}{\pi}]^{1/3}

we kow v = 16 \pi   so

h = 4 in

8 0
3 years ago
Is friction used when buttering a cake pan?
Elena L [17]

Answer: friction is used when 2 and 2 things mix and come together but normally friction slows things down but when buttering a pan it doesnt slow down

7 0
3 years ago
Read 2 more answers
Organisms that live on or burrow into the ocean floor are
creativ13 [48]
Benthos 

Option b is the answer



8 0
3 years ago
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The velocity of a 1.3 kg remote-controlled car is plotted on the graph. The work of segment A is J.
tamaranim1 [39]

Answer: 585 J

Explanation:

We can calculate the work done during segment A by using the work-energy theorem, which states that the work done is equal to the gain in kinetic energy of the object:

W=K_f -K_i

where Kf is the final kinetic energy and Ki the initial kinetic energy. The initial kinetic energy is zero (because the initial velocity is 0), while the final kinetic energy is

K_f =\frac{1}{2}mv^2

The mass is m=1.3 kg, while the final velocity is v=30 m/s, so the work done is:

W=K_f = \frac{1}{2}(1.3 kg)(30 m/s)^2=585 J

5 0
3 years ago
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how long would it take for a resultant upward force of 100N to increase the speed of 50kg object from 100m/s to 150m/s​
ValentinkaMS [17]

Answer:

25 sec

Explanation:

F = ma

100 = 50 a

a = 2 m/s^2

vf = vo + at

150 = 100 +  2 t

50 = 2 t

t = 25 sec

7 0
2 years ago
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