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3 years ago

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Edson exercises in sets that are each t minutes long. He does 6 sets of push-ups, 3 sets of pull-ups, and 4 sets of sit-ups. Use

an expression to represent the time it takes Edson to exercise as the sum of three different terms. Simplify the expression. Enter your answer in the box. The time it takes Edison to exercise is equal to t.

2 answers:

fiasKO [112]3 years ago

4 0

edson takes 130 minutes of exersise

step by step answer:

10 x 13 = 130

Nitella [24]3 years ago

3 0

Answer:

<h2>The expression would be 13t.</h2>

Explanation:

We know that:

Each set takes <em>t </em>minutes to be done.
Edson does three types of exercises with different sets: 6, 3 and 4.

Basically, we have to multiply each set by <em>t</em> minutes.

We have:

6 sets of push-ups: <em> t + t + t + t + t + t = 6t</em>
3 sets of pull-ups: <em>t + t + t = 3t</em>
4 sets of sit-ups: <em>t + t + t + t = 4t</em>

The total amount of time considering all sets is <em>6t + 3t + 4t = 13t. </em>In other words, Edson did 13 sets, if one set takes <em>t </em>minutes, then the 13 sets takes <em>13t </em>minutes.

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Answer:

Explanation:

(a)

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To find the final velocity( reflected velocity)

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Thus, the component along the x-axis = $v_2 \ cos \theta _r$

$v_{2x} = - 0.433 \ m/s$

The component along the y-axis = $v_2 \ sin \theta_r$

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(b)

The velocity $v_1$ can be written as in vector form.

$v_1 ^{\to} = v_1 x \hat {i} + v_1 y \hat {j}$

$v_1 ^{\to} =4.33 \ \hat {i} + 2.5 \ \hat {j}$ ---- (1)

The reflected velocity in vector form can be computed as:

$v_2 ^{\to} = v_2 x \hat {i} + v_2 y \hat {j}$

$v_2 ^{\to} =-4.33 \ \hat {i} + 2.5 \ \hat {j}$ --- (2)

The change in velocity = $v_2 ^{\to} - v_1 ^{\to}$

$\Delta v ^{\to} = - 4.33 \hat i + 2.5 \hat j - 4.33 \hat i - 2.5 \hat j$

$\Delta v ^{\to} = - 8.66 \hat { i }$

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The magnitude of change in velocity = $| \Delta V |$

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goldenfox [79]

According to Newton's 3rd law, there will be equal and opposite force on the astronaut which is -6048 N

<h3>What does Newton's third law say ?</h3>

The law state that in every action, there will be equal and opposite reaction.

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Let us first calculate the force involved in the acceleration of the rocket by using the formula

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According to the Newton's 3rd law, there will be equal and opposite force on the astronaut.

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GrogVix [38]

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<u>A) Impulse is the change of momentum of an object when the object is acted upon by a force for an interval of time. We use the formula:</u>

<em />

<em>/F/ = m. /Δv/</em>

<u>Where:</u>

F= Force of Impulse

m= Mass

Δv= change in speed ( vf-vi)

Using that formula we get:

/F/= 0,90kg . / (0m/s-14m/s) /

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<em>/F/ = 11,7 kg. m/s</em>

*note that (vf) is 0 because the hand stops in the action, so it's final

velocity = 0

<u>B)The average force is equal to the change in the momentum over the change in time. We use the formula:</u>

<em>/F/= m. (Δv) : Δt</em>

<u>Where:</u>

F= the average force from the target

m= the mass of the hand

Δv= hange in speed (vf/vi)

Δt= change in time

*if we look closely, we find the we alredy have half of the equation because we have alredy calculated m.(Δv) in point A.

We boil the equation down to:

/F/= Impulse : Δt

/F/= 11,7kg.m/s : 0,003s

<em>/F/= 3900N</em>

*we use 0,003s as our time because the given time was 3ms.

*the final result is expressed in Newtons because our final result ends up beeing <em>kg.m/s²</em> = N

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