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fredd [130]
3 years ago
7

Edson exercises in sets that are each t minutes long. He does 6 sets of push-ups, 3 sets of pull-ups, and 4 sets of sit-ups. Use

an expression to represent the time it takes Edson to exercise as the sum of three different terms. Simplify the expression. Enter your answer in the box. The time it takes Edison to exercise is equal to t.
Physics
2 answers:
fiasKO [112]3 years ago
4 0

edson takes 130 minutes of exersise



step by step answer:

10 x 13 = 130

Nitella [24]3 years ago
3 0

Answer:

<h2>The expression would be 13t.</h2>

Explanation:

We know that:

  • Each set takes <em>t </em>minutes to be done.
  • Edson does three types of exercises with different sets: 6, 3 and 4.

Basically, we have to multiply each set by <em>t</em> minutes.

We have:

  • 6 sets of push-ups: <em> t + t + t + t + t + t = 6t</em>
  • 3 sets of pull-ups: <em>t + t + t = 3t</em>
  • 4 sets of sit-ups: <em>t + t + t + t = 4t</em>

The total amount of time considering all sets is <em>6t + 3t + 4t = 13t. </em>In other words, Edson did 13 sets, if one set takes <em>t </em>minutes, then the 13 sets takes <em>13t </em>minutes.

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An automobile starter motor has an equivalent resistance of 0.0500Ω and is supplied by a 12.0-V battery with a 0.0100-Ω internal
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Answer

given,

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internal resistance of battery = 0.01 Ω

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a) ohm's law

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     and volage

   V = \epsilon - Ir

now,

   IR = \epsilon - Ir

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inserting the values

   I= \dfrac{12}{0.05+0.01}

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c) Power

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6 0
3 years ago
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A train travels 85 kilometers in 5 hours, and then 63 kilometers in 5 hours what is its average speed?
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a water bomber flying with a horizontal speed of 85m/s at a height of 3000m drops a load on a fire below. How far in front of th
Andreyy89

Answer:

2081.65 m

Explanation:

We'll begin by calculating the time taken for the load to get to the target. This can be obtained as follow:

Height (h) = 3000 m

Acceleration due to gravity (g) = 10 m/s²

Time (t) =?

h = ½gt²

3000 = ½ × 10 × t²

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Divide both side by 5

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Take the square root of both side

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Finally, we shall determine the distance from the target at which the load should be released. This can be obtained as follow:

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