3.5 moles of ammonia (NH₃) are produced
Explanation:
We have the following chemical reaction where hydrogen (H₂) reacts with nitrogen (N₂) to produce ammonia (NH₃):
3 H₂ + N₂ → 2 NH₃
number of moles = mass / molecular weight
number of moles of N₂ = 48.97 / 28 = 1.75 moles
We see from the chemical reaction that 1 mole of N₂ will react with 3 moles of H₂, so 1.75 moles of nitrogen will react with 3 × 1.75 = 5.25 moles of H₂. We have 7.32 moles of H₂, a quantity more of what is needed, so the limiting reactant is N₂.
Knowing this we devise the following reasoning:
if 1 mole of N₂ produces 2 moles of NH₃
then 1.75 moles of N₂ produces X moles of NH₃
X = (1.75 × 2) / 1 = 3.5 moles of NH₃
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limiting reactant
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Answer:- Mass of the alloy is 2.8 kg.
Solution:- Mass of Cr in the alloy is 325 g and mass of Fe in the alloy is 2.5 kg. Mass of alloy would be the sum of masses of constituent metals.
Masses of the metals are not in the same units. So, we need to make the units equal. The want answer in kg so let's convert mass of Cr from g to kg.
Since, 1000 g = 1 kg
So, 
= 0.325 kg
Mass of alloy = mass of Cr + mass of Fe
mass of alloy = 0.325 kg + 2.5 kg = 2.825 kg
If we consider significant figures then as per the rules, the answer should not have more than one decimal place.
So, 2.825 kg is round off to 2.8 kg and hence the mass of the alloy is 2.8 kg.
The first and Third graph