Answer:
-64.0 m/s²
Explanation:
v = 32.0 t − 2.00 t³
Acceleration is the derivative of velocity.
a = dv/dt
a = 32.0 − 6.00 t²
At maximum displacement, v = 0 and a < 0.
v = 0
32.0 t − 2.00 t³ = 0
2.00 t (16.0 − t²) = 0
t = 0 or 4.00
When t = 0 s, a = 32.0 m/s².
When t = 4.00 s, a = -64.0 m/s².
The maximum displacement is at t = 4.00 s. Therefore, the acceleration at that moment is -64.0 m/s².
Here is what can help you. Sorry I could not find the answer. Best of luck!
The Newton's Laws that BEST describe the situation is Newton's second law of motion.
<h3>
What is Newton's second law of motion?</h3>
Newton's second law of motion states, the force exerted by an object is directly proportional to the product of mass and acceleration of the object.
Also, the law can also be states as force is equal to the rate of change of momentum.
F ∝ Δp
Ft = m(v2 - v1)
The force exerted on the bicyclist by the fence is equal to the change in momentum of the bicyclist. The bicyclist was able to fly over the fence because there is a change in his momentum.
Thus, the Newton's Laws that BEST describe the situation is Newton's second law of motion.
Learn more about Newton's second law of motion here: brainly.com/question/3999427
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Draw a diagram to illustrate the problem as shown in the figure below.
Camp A is 20° north of east from the camp, therefore
m∠CAB = 80°
where C => base camp.
Let d = distance from lake B to the base camp, at x° west of south.
Apply the Law of Cosines to determine d.
d² = 205² + 175² - 2*205*175*cos80⁰
= 6.0191 x 10⁴
d = 245.338 km
Apply the Law of Sines to obtain
x+30 = sin⁻¹ 0.8229 = 55.4°
x = 25.4°
Answer:
The distance from lake B to base camp is 243.3km (nearest tenth).
The direction is 25.4° west of south.
Answer
Given,
Magnetic field, B = 0.0000193 T
speed, v = 121 m/s
mass of electron, m = 9.11 x 10⁻³¹ Kg
charge of electron, q = 1.6 x 10⁻¹⁹ C
radius of the electron path, r = ?
r = 3.64 x 10⁻⁵ m
We know frequency is inverse of time period
d = v t
t = 1.889 x 10⁻⁶ s.
now, frequency