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lesya [120]
3 years ago
8

Forces that are equal in size but opposite in direction are ____. a. balanced forces c. inertial forces b. frictional forces d.

net forces
Physics
2 answers:
Brrunno [24]3 years ago
6 0
Hi Billy

Forces that are equal in size but opposite in direction are called : Balanced forces.

The answer is : A

Good luck !
loris [4]3 years ago
6 0
The answer will be a. Balanced Forces.
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26. The problem with calculating the speed of an object simply by dividing distance by time is​
Gekata [30.6K]

Answer:

We obtain the average velocity instead of the instantaneus velocity.

Explanation:

The problem with calculating speed in this way is that an average speed is being calculated and not an instantaneous speed at a given point.

V_{average} =\frac{x}{t} \\where:\\x = distance\\t = interval of time

To calculate the instantaneous speed, a very small space interval must be measured at a given time.

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3 years ago
What does the force of friction between two objects in context depend on?
xenn [34]

The amount of friction depends on the force pushing the surfaces together. If this force increases, the hills and valleys of the surfaces can come into closer contact. The close contact increases the friction between the surfaces.

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3 years ago
A playground merry-go-round of radius R = 1.80 m has a moment of inertia I = 270 kg · m2 and is rotating at 8.0 rev/min about a
Arte-miy333 [17]

Answer:

\dot n = 6.042\,rpm

Explanation:

The final angle speed of the merry-go-round is determined with the help of the Principle of Angular Momentum Conservation:

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3 0
3 years ago
A student coils a copper wire around a bar magnet. What action will cause the device to generate electricity?
kolbaska11 [484]

I hope the wire is not wound too tightly around the bar magnet.
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6 0
3 years ago
A boy jumps from rest, straight down from the top of a cliff. He falls halfway down to the water below in 0.866 s. How much time
Iteru [2.4K]
<h2>Entire trip takes 1.22 seconds.</h2>

Explanation:

We have equation of motion s = ut + 0.5 at²

        Initial velocity, u = 0 m/s

        Acceleration, a = 9.81 m/s²  

        Time, t = 0.866 s      

     Substituting

                      s = ut + 0.5 at²

                      s = 0 x 0.866 + 0.5 x 9.81 x 0.866²

                      s = 3.68 m

      Halfway is 3.68 m

Total height = 2 x 3.68 = 7.36 m

We have equation of motion s = ut + 0.5 at²

        Initial velocity, u = 0 m/s

        Acceleration, a = 9.81 m/s²  

        Time, t = ?

        Displacement, s  = 7.36 m

     Substituting

                      s = ut + 0.5 at²

                      7.36 = 0 x t + 0.5 x 9.81 x t²

                      t = 1.22 s

Entire trip takes 1.22 seconds.

7 0
3 years ago
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