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PolarNik [594]
3 years ago
6

A compound has the empirical formula CH and a molar mass of 78.11 g/mol . Find its molecular formula.

Chemistry
2 answers:
Reil [10]3 years ago
7 0

Answer:

Molecular Formula = C6H6

Explanation:

Empirical Formular = CH

Molar Mass = 78.11

Molecular Formular = ?

The Formular relating these parameters is given as;

(Empirical Formula)n = Molecular Formular

where n = Number of moles

CH = 12.0107 + 1.00784 = 13.01854

(13.01854)n = 78.11

n = 78.11 / 13.01854

n = 5.9999 ≈ 6

Molecular Formula = C6H6

lianna [129]3 years ago
3 0

Answer:

C - 12.01 g/mol

H - 1.008 g/mol

CH - 13.018g/mol

molecular formula = n×(empirical formula)

       78.11 g/mol     = n ×( 12.01 + 1.008) g/mol

       ∴ n = 5.99

        ≈ 6

then C_{6} H_{6}

Explanation: First find the molar mass of the empirical formula CH.

use the formula that says: Molecular formula = n × empirical formula

therefore you divide the molar mass of the compound by molar mass of the empirical formula.

the empirical is the 6th and then multiply that 6 with the subscripts of CH.

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What volume (in milliliters) of oxygen gas is required to react with 4.03 g of Mg at STP
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7 0
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Answer:

\boxed{yeah}

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