It can be explained as follows: consider the field produced by a positive charge. If we place a positive test charge in this a field, then this charge would move away from the central charge (because like charges repel), while if we place a negative test charge in this field, this charge would move towards the central charge (because opposite charges repel)
Explanation:
Electric fields are vector fields, and they are represented using field lines.
The field lines give indications on both the magnitude and the direction of the electric field. In fact:
- The magnitude of the field can be inferred from the spacing between the lines: the closer the lines are, the stronger the field, while for a weaker field the lines are more spread apart
- The direction of the field is given by the direction of the field lines
In particular, by convention the direction of the field lines represent the direction of the force that a positive test charge would feel when immersed in that field: this means that a positive test charge would accelerate in the direction of the field lines, while a negative test charge would accelerate in the direction opposite to the field lines.
This is in agreement with the fact that like charges repel and opposite charges attract. In fact, the lines of the electric field produced by a single-point positive charge point away from the positive charge: if we place a positive test charge in this field, then this charge would move away from the central charge (because like charges repel), while if we place a negative test charge in this field, this charge would move towards the central charge (because opposite charges repel).
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Answer:
-0.8 m/s²
Explanation:
Acceleration is the slope of a velocity vs. time graph.
a = Δv / Δt
a = (0 m/s − 12 m/s) / (15 s − 0 s)
a = -0.8 m/s²
Answer:
B: leaving metal outside in the rain until rust forms an it's surface
The difference in weight is due to the
displacement of water (the buoyancy of water is acting on the athlete thus
giving her smaller weight).<span>
The amount of weight displaced or the amount of buoyant force
is: </span>
Fb = 690 N - 48 N
Fb = 642 N
From newtons law, F = m*g. Using this formula, we
can calculate for the mass of water displaced:
m of water displaced = 642N / 9.8m/s^2
m of water displaced = 65.5 kg
Assuming a water density of 1 kg/L, and using the
formula volume = mass/density:
V of water displaced = 65.5kg / 1kg/L = 65.5 L
The volume of water displaced is equal to the
volume of athlete. Therefore:
V of athlete = 65.5 L
The mass of athlete can also be calculated using,
F = m*g
m of athlete = 690 N/ 9.8m/s^2
m of athlete = 70.41 kg
Knowing the volume and mass of athlete, her
average density is therefore:
average density = 70.41 kg / 65.5 L
<span>average density = 1.07 kg/L = 1.07 g/mL</span>
