NH3(g)+HCI(g⇒)NH4CI(s)

Write a balanced equation for the double replacement neutralization reaction described using the smallest possible integer coeff

tatuchka [14]

Answer:

The answer to your question is Ba(OH)₂ + 2HClO₄ ⇒ Ba(ClO₄)₂ + 2H₂O

Explanation:

Reactants

Barium hydroxide

Perchloric acid

Formula

Barium hydroxide = Ba(OH)₂

Perchloric acid = HClO₄

Equation (it is a double replacement)

Ba(OH)₂ + HClO₄ ⇒ Ba(ClO₄)₂ + H₂O

Reactants Elements Products

1 Ba 1

1 Cl 2

3 H 2

6 O 9

This reaction is unbalanced

2) Balance the chemical reaction

Ba(OH)₂ + 2HClO₄ ⇒ Ba(ClO₄)₂ + 2H₂O

Reactants Elements Products

1 Ba 1

2 Cl 2

4 H 4

10 O 10

Now the reaction is balanced

Products

Ba(ClO₄)₂ Barium perchloride

2H₂O water

3 0

3 years ago

In the reaction of 1.23 g of salicylic acid, molar mass 138.12 g/mol, with 2.85 g of acetic anhydride, molar mass 102.10 g/mol,

Rudik [331]

The balanced reaction would be written as:
C7H6O3 + C4H6O3--->C9H8O4 + HC2H3O2
To determine the percent yield, we need to first determine the theoretical yield if the reaction were to proceed completely. Then, we divide the actual yield that is given to the theoretical yield times 100 percent. The limiting reactant from the reaction would be salicylic acid. We do as follows:

Theoretical yield: 1.23 g C7H6O3 ( 1 mol / 138.21 g ) ( 1 mol C9H8O4 / 1 mol C7H6O3 ) ( 180.157 g / mol ) = 1.60 g C9H8O4 should be produced

Percent yield = 1.39 / 1.60 x 100 = 86.88%

Thus, only 86.88% of the theoretical C9H8O4 is being produced.

7 0

3 years ago

From standard reduction potentials, calculate the equilibrium constant at 25 ∘c for the reaction 2mno−4(aq)+10cl−(aq)+16h+(aq)→2

garik1379 [7]

Answer:

$\boxed{\text{57.9}}$

Explanation:

Step 1. Determine the cell potential

E°/V

2MnO₄⁻ + 16H⁺ + 10e⁻ → 2Mn²⁺+ 8H₂O 1.507

10Cl⁻ ⟶ 5Cl₂ + 10e⁻ -1.358 27

2MnO₄⁻ + 10Cl⁻ + 16H⁺⟶ 2Mn²⁺ + 5Cl₂ + 8H₂O 0.149

Step 2. Calculate K

The formula relating K and E is

$E = \dfrac{RT}{nF} \ln K$

E = 0.149 V

R = 8.314 J·K⁻¹mol⁻¹

T = 25 °C = 298.15 K

n = 10

F = 96 485 C/mol

$0.149 = \dfrac{8.314 \times 298.15}{10\times 96 485} \ln K\\\\0.149 = 0.002 570 \ln K\\\\\ln K = \dfrac{0.149}{0.002570} = \textbf{57.9}$

The value of the equilibrium constant is $\boxed{\textbf{57.9}}$

6 0

2 years ago

Calculate the mass of feso4 that would be produced by 0.5mole of Fe

densk [106]

Answer:76 grams

Explanation:

Fe+H₂SO₄-->FeSO₄+H₂

For one mole of Fe we get 1 mole of feso4, therefore for 0.5 moles of Fe we get 0.5 moles of feso4.

The molar mass of feso4 is AFe+AS+4AO(A is atomic mass)

56+32+4*16=152grams/mole

Now, we need to multiply the number of moles by the molar mass to get the mass that reacts

152*0.5=76 grams

8 0

2 years ago

What types of emergency situations could rescue workers be in that would make it difficult for them to get energy to their elect

artcher [175]

Answer:

Large-scale natural disasters

Explanation:

The emergency situation that rescue workers could be in that would make it difficult for them to get energy to their electrical devices is "Large-scale natural disasters"

Large-scale natural disasters are very destructive and devastating. Their impact and effect can range from destruction of infrastructures, properties, social amenities and even ecosystems. When such disasters break out, they destroy things and which leads to difficulty in accessing certain amenities. Rescue workers even find it difficult to access energy for their electrical devices - because there is power outage.

Some of these large-scale natural disasters are earthquakes, tornadoes, hurricanes, floods, etc.

4 0

3 years ago