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laiz [17]
3 years ago
11

When you boil a pot of liquid water, the water turns to steam and rises in the air. This is an example of what.

Chemistry
2 answers:
Thepotemich [5.8K]3 years ago
5 0

Answer:

C: evaporation

Explanation:

this is a liquid to gas, so evaporation matches this scenario

hope this helps! Please give brainiest!!! ty

Georgia [21]3 years ago
4 0

Answer:

Hello There!!

Explanation:

The answer is C: evaporation because evaporation is the process in which a liquid boils then evaporates and lastly becomes a gas.

hope this helps,have a great day!!

~Pinky~

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Consider the following reaction:
adell [148]

Answer:

1. d[H₂O₂]/dt = -6.6 × 10⁻³ mol·L⁻¹s⁻¹; d[H₂O]/dt = 6.6 × 10⁻³ mol·L⁻¹s⁻¹

2. 0.58 mol

Explanation:

1.Given ΔO₂/Δt…

    2H₂O₂     ⟶      2H₂O     +     O₂

-½d[H₂O₂]/dt = +½d[H₂O]/dt = d[O₂]/dt  

d[H₂O₂]/dt = -2d[O₂]/dt = -2 × 3.3 × 10⁻³ mol·L⁻¹s⁻¹ = -6.6 × 10⁻³mol·L⁻¹s⁻¹

 d[H₂O]/dt =  2d[O₂]/dt =  2 × 3.3 × 10⁻³ mol·L⁻¹s⁻¹ =  6.6 × 10⁻³mol·L⁻¹s⁻¹

2. Moles of O₂  

(a) Initial moles of H₂O₂

\text{Moles} = \text{1.5 L} \times \dfrac{\text{1.0 mol}}{\text{1 L}} = \text{1.5 mol }

(b) Final moles of H₂O₂

The concentration of H₂O₂ has dropped to 0.22 mol·L⁻¹.

\text{Moles} = \text{1.5 L} \times \dfrac{\text{0.22 mol}}{\text{1 L}} = \text{0.33 mol }

(c) Moles of H₂O₂ reacted

Moles reacted = 1.5 mol - 0.33 mol = 1.17 mol

(d) Moles of O₂ formed

\text{Moles of O}_{2} = \text{1.33 mol H$_{2}$O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{2 mol H$_{2}$O}_{2}} = \textbf{0.58 mol O}_{2}\\\\\text{The amount of oxygen formed is $\large \boxed{\textbf{0.58 mol}}$}

8 0
3 years ago
Why is this image a good model for the Law of Conservation of Mass?
ZanzabumX [31]

Answer:

The Law of Conservation of Mass states that mass is neither created nor destroyed in chemical reactions. Since the number and type of atoms in the reactant side of the chemical equation are the same as on the product side, the Law of Conservation of Mass has been demonstrated.

Explanation:

In the answer.

8 0
3 years ago
Na2CrO4 + PbCL2<br> Formula in double replacement
Marta_Voda [28]

Na₂CrO₄ + PbCl₂ → PbCrO₄ + 2 NaCl

<u>Explanation:</u>

In a double displacement reaction, the reactants which are involved in the reaction exchanging their ions thereby produces 2 new compounds. Here sodium chromate and lead chloride are undergoing double displacement reaction, the ions exchanges their position there by forming sodium chloride and lead chromate. So the double displacement reaction is given as,

Na₂CrO₄ + PbCl₂ → PbCrO₄ + 2 NaCl

6 0
3 years ago
Which pair of elements have the same valence electronic configuration of np³?
Dennis_Churaev [7]

Answer:

(c) P and Sb

Explanation:

We can determine the number of valence electrons of an element:

  • If it belongs to Groups 1 and 2, the number of valence electrons is equal to the number of group and the differential electron occupies the s subshell.
  • If it belongs to the groups 13-18, the number of valence electrons is equal to: "Number of group - 10" and the differential electron occupies the p subshell.

Which pair of elements have the same valence electronic configuration of np³?

(a) O and Se. NO. They belong to the group 16 and the valence electron configuration is ns² np⁴.

(b) Ge and Pb. NO. They belong to the group 14 and the valence electron configuration is ns² np².

(c) P and Sb. YES. They belong to the group 15 and the valence electron configuration is ns² np³.

(d) K and Mg. NO. They belong to the groups 1 and 2 and the valence electron configuration is ns¹ and ns².

(e) Al and Ga. NO. They belong to the group 13 and the valence electron configuration is ns² np¹.

5 0
3 years ago
What is the next atomic orbital in the series 1s 2p 3s 3p
liq [111]

Answer:

s an example, the ground state configuration of the sodium atom is 1s22s22p63s1, as deduced from the Aufbau principle (see below). The first excited state is obtained by promoting a 3s electron to the 3p orbital, to obtain the 1s22s22p63p1 configuration, abbreviated as the 3p level.

Explanation:

3 0
3 years ago
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