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vekshin1
4 years ago
6

What is the speed of a rocket in m/s that travels 900 meters in 12.12 seconds

Physics
1 answer:
nata0808 [166]4 years ago
7 0
U=s/t
u=74 m/s almost
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Which two statements offer evidence that the clocks energy is conserved?
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C is the best answer because we all know that clock is part of our daily lives but we don't know the about its background

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How much current does a 10.0 Ω resistor draw from a 12 V battery?
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An electron and a 0.033 0-kg bullet each have a velocity of magnitude 495 m/s, accurate to within 0.010 0%. Within what lower li
lara31 [8.8K]

Answer:

1.170*10^-3 m

3.23*10^-32 m

Explanation:

To solve this, we apply Heisenberg's uncertainty principle.

the principle states that, "if we know everything about where a particle is located, then we know nothing about its momentum, and vice versa." it also can be interpreted as "if the uncertainty of the position is small, then the uncertainty of the momentum is large, and vice versa"

Δp * Δx = h/4π

m(e).Δv * Δx = h/4π

If we make Δx the subject of formula, by rearranging, we have

Δx = h / 4π * m(e).Δv

on substituting the values, we have

for the electron

Δx = (6.63*10^-34) / 4 * 3.142 * 9.11*10^-31 * 4.95*10^-2

Δx = 6.63*10^-34 / 5.67*10^-31

Δx = 1.170*10^-3 m

for the bullet

Δx = (6.63*10^-34) / 4 * 3.142 * 0.033*10^-31 * 4.95*10^-2

Δx = 6.63*10^-34 / 0.021

Δx = 3.23*10^-32 m

therefore, we can say that the lower limits are 1.170*10^-3 m for the electron and 3.23*10^-32 for the bullet

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4 years ago
A 0.10 kg mass is oscillating at a small angle from a light string of length 0.10 m.
cupoosta [38]

Answer:

tough

Explanation:

5 0
2 years ago
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