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3 years ago

What are the horizontal and vertical parts of vectors called

1 answer:

7 0

A 2-dimensional vector may be expressed by
A = Ax i + Ay j
where i and j are unit vectors along the x (horizontal) and y (vertical) axes respectively.
Ax = horizontal part (x-component)
Ay = vertical part (y-component)

Alternatively, the vector may be written as
A = (Ax, Ay)

Answer:
Horizontal part = x-component
Vertical part = y-component

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A train starts at rest in a station and accelerates at a constant 0.987 m/s2 for 182 seconds. Then the train decelerates at a co

algol [13]

Answer:

$\displaystyle X_T=66.6\ km$

Explanation:

<u>Accelerated Motion </u>

When a body changes its speed at a constant rate, i.e. same changes take same times, then it has a constant acceleration. The acceleration can be positive or negative. In the first case, the speed increases, and in the second time, the speed lowers until it eventually stops. The equation for the speed vf at any time t is given by

$\displaystyle V_f=V_o+a\ t$

where a is the acceleration, and vo is the initial speed .

The train has two different types of motion. It first starts from rest and has a constant acceleration of $0.987 m/s^2$ for 182 seconds. Then it brakes with a constant acceleration of $-0.321 m/s^2$ until it comes to a stop. We need to find the total distance traveled.

The equation for the distance is

$\displaystyle X=V_o\ t+\frac{a\ t^2}{2}$

Our data is

$\displaystyle V_o=0,a=0.987m/s^2,\ t=182\ sec$

Let's compute the first distance X1

$\displaystyle X_1=0+\frac{0.987\times 182^2}{2}$

$\displaystyle X_1=16,346.7\ m$

Now, we find the speed at the end of the first period of time

$\displaystyle V_{f1}=0+0.987\times 182$

$\displaystyle V_{f1}=179.6\ m/s$

That is the speed the train is at the moment it starts to brake. We need to compute the time needed to stop the train, that is, to make vf=0

$\displaystyle V_o=179.6,a=-0.321\ m/s^2\ ,V_f=0$

$\displaystyle t=\frac{v_f-v_o}{a}=\frac{0-179.6}{-0.321}$

$\displaystyle t=559.5\ sec$

Computing the second distance

$\displaystyle X_2=179.6\times559.5\ \frac{-0.321\times 559.5^2}{2}$

$\displaystyle X_2=50,243.2\ m$

The total distance is

$\displaystyle X_t=x_1+x_2=16,346.7+50,243.2$

$\displaystyle X_t=66,589.9\ m$

$\displaystyle \boxed{X_T=66.6\ km}$

8 0

3 years ago

A man ran the 200m race within 19.19 seconds. Calculate the speed of the man during the race

natta225 [31]

Answer:

around 23 miles per hour

4 0

3 years ago

Why dont streams flow horizontal

mylen [45]

Answer:

because

Explanation:

streasm dont flow horizontal because if it did then that would be breaking all laws of physics and we know that what goes up must com down but water cant flow upstream only down if it does flow horizontally then it would either be between two hills or in a plains

7 0

3 years ago

What are the different types of<br> technology?

LUCKY_DIMON [66]

Answer:

well theirs health, idustry, transport, comunication, information tech, and plenty more

Explanation:

can i plz have brainlyest it helps me continew helping people like you

3 0

3 years ago

Suppose a 1500 kg speed boat is traveling with a velocity of 30 m/s what is the speed boats Monument

DanielleElmas [232]

Answer: 45000kgm/s

Explanation:

Given that:

Mass of speed boat = 1500 kg

Velocity of speedboat = 30 m/s

Speed boats Momentum = ?

The Speed boat momentum is the product of its mass and the velocity by which it moves. Momentum is a vector quantity and measured in kgm/s

i.e Momentum = mass x velocity

= 1500 kg x 30 m/s

= 45000kgm/s

Thus, the speed boats momentum is 45000kgm/s

7 0

3 years ago