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3 years ago

Which device uses AC current to operate?

Physics

2 answers:

sweet [91]3 years ago

6 0

Answer

Correct option is B that is Desktop computer

Explanation

Option A

This option is not correct because in a Locomotive train steam, diesel or batteries are used.

Option B

It is Correct option because in desktop a transformer is there which uses AC current. Most of us have desktop and we used AC current to operate it we don't have any other option to operate a desktop except AC current

Option C

This is not correct option because in a car we used petrol, deisel, gas or DC batteries.

Option D

Option D is not correct option because to operate portable media player we can use both alternating current or batteries

Option

This is not correct option because in flashlight we uses DC batteries

Hope this answer will help you

xz_007 [3.2K]3 years ago

5 0

B. Desktop computer

A Locomotive train runs on steam, diesel, or batteries

a car either gas or electric uses DC batteries

portable media player can use AC or batteries

A flashlight uses DC batteries

The computer actually has a transformer built into it which uses AC current

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On Earth, 1 g = 9.8 m/s² .

5 g = 5 · (9.8 m/s²)

5 g = 49 m/s²

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3 years ago

Tom has two pendulums with him. Pendulum 1 has a ball of mass 0.2 kg attached to it and has a length of 5 m. Pendulum 2 has a ba

mars1129 [50]

Given Information:

Pendulum 1 mass = m₁ = 0.2 kg

Pendulum 2 mass = m₂ = 0.6 kg

Pendulum 1 length = L₁ = 5 m

Pendulum 2 length = L₂ = 1 m

Required Information:

Affect of mass on the frequency of the pendulum = ?

Answer:

The mass of the ball will not affect the frequency of the pendulum.

Explanation:

The relation between period and frequency of pendulum is given by

f = 1/T

The period of pendulum is given by

T = 2π√(L/g)

Where g is the acceleration due to gravity and L is the length of the string

As you can see the period (and frequency too) of pendulum is independent of the mass of the pendulum. Therefore, the mass of the ball will not affect the frequency of the pendulum.

Bonus:

Pendulum 1:

T₁ = 2π√(L₁/g)

T₁ = 2π√(5/9.8)

T₁ = 4.49 s

f₁ = 1/T₁

f₁ = 1/4.49

f₁ = 0.22 Hz

Pendulum 2:

T₂ = 2π√(L₂/g)

T₂ = 2π√(1/9.8)

T₂ = 2.0 s

f₂ = 1/T₂

f₂ = 1/2.0

f₂ = 0.5 Hz

So we can conclude that the higher length of the string increases the period of the pendulum and decreases the frequency of the pendulum.

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3 years ago

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Answer:

(1) passed through the foil

Explanation:

Ernest Rutherford conducted an experiment using an alpha particle emitter projected towards a gold foil and the gold foil was surrounded by a fluorescent screen which glows upon being struck by an alpha particle.

When the experiment was conducted he found that most of the alpha particles went away without any deflection (due to the empty space) glowing the fluorescent screen right at the point of from where they were emitted.

While a few were deflected at reflex angle because they were directed towards the center of the nucleus having the net effective charge as positive.

And some were acutely deflected due to the field effect of the positive charge of the proton inside the nucleus. All these conclusions were made based upon the spot of glow on the fluorescent screen.