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4 years ago

Which device uses AC current to operate?

Physics

2 answers:

sweet [91]4 years ago

6 0

Answer

Correct option is B that is Desktop computer

Explanation

Option A

This option is not correct because in a Locomotive train steam, diesel or batteries are used.

Option B

It is Correct option because in desktop a transformer is there which uses AC current. Most of us have desktop and we used AC current to operate it we don't have any other option to operate a desktop except AC current

Option C

This is not correct option because in a car we used petrol, deisel, gas or DC batteries.

Option D

Option D is not correct option because to operate portable media player we can use both alternating current or batteries

Option

This is not correct option because in flashlight we uses DC batteries

Hope this answer will help you

xz_007 [3.2K]4 years ago

5 0

B. Desktop computer

A Locomotive train runs on steam, diesel, or batteries

a car either gas or electric uses DC batteries

portable media player can use AC or batteries

A flashlight uses DC batteries

The computer actually has a transformer built into it which uses AC current

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Explanation:

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3 years ago

An aseroid with a mass of 8.4x10^8 kg and a planet with a mass of 6.2x10^23 kg come close to each other by a distance of 8x10^5

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So, the force of gravity that the asteroid and the planet have on each other approximately

$\boxed{\sf{5.43 \times 10^{10} \: N}}$

<h3>Introduction</h3>

Hi ! Now, I will help to discuss about the gravitational force between two objects. We already know that <u>gravitational force occurs when two or more objects interact with each other at a certain distance and generally orbit each other to their center of mass</u>. For the gravitational force between two objects, it can be calculated using the following formula :

$\boxed{\sf{\bold{F = G \times \frac{m_1 \times m_2}{r^2}}}}$

With the following condition :

F = gravitational force (N)
G = gravity constant ≈ $\sf{6.67 \times 10^{-11}}$ N.m²/kg²
$\sf{m_1}$ = mass of the first object (kg)
$\sf{m_2}$ = mass of the second object (kg)
r = distance between two objects (m)

<h3>Problem Solving</h3>

We know that :

G = gravity constant ≈ $\sf{6.67 \times 10^{-11}}$ N.m²/kg²
$\sf{m_1}$ = mass of the first object = $\sf{8.4 \times 10^8}$ kg.
$\sf{m_2}$ = mass of the second object = $\sf{6.2 \times 10^{23}}$ kg.
r = distance between two objects = $\sf{8 \times 10^5}$

What was asked :

F = gravitational force = ... N

Step by step :

$\sf{F = G \times \frac{m_1 \times m_2}{r^2}}$

$\sf{F = 6.67 \times 10^{-11} \times \frac{8.4 \cdot 10^8 \times 6.2 \cdot 10^{23}}{(8 \times 10^5)^2}}$

$\sf{F = \frac{347.374 \times 10^{-11 + 8 + 23}}{64 \times 10^10}}$

$\sf{F \approx 5.43 \times 10^{20 - 10}}$

$\boxed{\sf{F \approx 5.43 \times 10^{10} \: N}}$

<h3>Conclusion</h3>

So, the force of gravity that the asteroid and the planet have on each other approximately

$\boxed{\sf{5.43 \times 10^{10} \: N}}$

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2 years ago

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3 years ago

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Answer:

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Explanation:

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$2\cdot h = v\cdot t$ (1)