Empirical formula is the simplest ratio of components making up a compound.
The percentage composition of each element has been given
therefore the mass present of each element in 100 g of compound is
B N H
mass 40.28 g 52.20 g 7.53 g
number of moles
40.28 g / 11 g/mol 52.20 g / 14 g/mol 7.53 g / 1 g/mol
= 3.662 mol = 3.729 mol = 7.53 mol
divide the number of moles by the least number of moles, that is 3.662
3.662 / 3.662 3.729 / 3.662 7.53 / 3.662
= 1.000 = 1.018 = 2.056
the ratio of the elements after rounding off to the nearest whole number is
B : N : H = 1 : 1 : 2
therefore empirical formula for the compound is B₁N₁H₂
that can be written as BNH₂
Answer:
In the presence of a base, blue litmus paper will turn red........
Answer:
D. +5.7 kJ/mol
Explanation:
Molar free energy (ΔG) in the transportation of uncharged molecules as glucse through a cell membrane from the exterior to the interior of the cell is defined as:
ΔG = RT ln C in / C out
knowing R is 8,314472 kJ/molK; T is 298K Cin = 200mM and Cout = 20mM
ΔG = 5,7 kJ/mol
Right answer is:
D. +5.7 kJ/mol
I hope it helps!
It has 4 significant figures. If you see the Zero after the one decimal point you don’t count that and instead just started at 6
