Answer:
The reaction would shift toward the reactants
When the reaction reach equilibrium the partial pressure of NH3 will be greater than 1atm
Explanation:
For the reaction:
2NH₃(g) ⇄ N₂(g) + 3H₂(g)
Where K is defined as:
![K = \frac{P_{N_{2}}*P_{H_2}^3}{P_{NH_3}^2} = 0.83](https://tex.z-dn.net/?f=K%20%3D%20%5Cfrac%7BP_%7BN_%7B2%7D%7D%2AP_%7BH_2%7D%5E3%7D%7BP_%7BNH_3%7D%5E2%7D%20%3D%200.83)
As initial pressures of all 3 gases is 1.0atm, reaction quotient, Q, is:
![Q = \frac{1atm*{1atm}^3}{1atm^2} = 1](https://tex.z-dn.net/?f=Q%20%3D%20%5Cfrac%7B1atm%2A%7B1atm%7D%5E3%7D%7B1atm%5E2%7D%20%3D%201)
As Q > K, <em>the reaction will produce more NH₃ until Q = K consuming N₂ and H₂.</em>
Thus, there are true:
<h3>The reaction would shift toward the reactants</h3><h3>When the reaction reach equilibrium the partial pressure of NH3 will be greater than 1atm</h3>
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Answer:
an object that is at rest will stay at rest inless a force acts upon it.
An oject that is in motion will not change its velocity unless a force acts upon it.
Answer:
101,37°C
Explanation:
Boiling point elevation is one of the colligative properties of matter. The formula is:
ΔT = kb×m <em>(1)</em>
Where:
ΔT is change in boiling point: (X-100°C) -X is the boiling point of the solution-
kb is ebulloscopic constant (0,52°C/m)
And m is molality of solution (mol of ethylene glycol / kg of solution). Moles of ethylene glycol (MW: 62,07g/mol):
203g × (1mol /62,07g) = <em>3,27moles of ethlyene glycol</em>
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Molality is: 3,27moles of ethlyene glycol / (1,035kg + 0,203kg) = 2,64m
Replacing these values in (1):
X - 100°C = 0,52°C/m×2,64m
X - 100°C = 1,37°C
<em>X = 101,37°C</em>
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I hope it helps!
The answer is metal. Metals are always named first in ionic compounds, like KNO3 for example. I hope this helps!
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ANSWER: