Answer:
The number of turns in the solenoid is 230.
Explanation:
Given that,
Rate of change of current, 
Induced emf, 
Current, I = 1.5 A
Magnetic flux, 
The induced emf through the solenoid is given by :
or
........(1)
The self inductance of the solenoid is given by :
.........(2)
From equation (1) and (2) we get :
N is the number of turns in the solenoid
N = 229.28 turns
or
N = 230 turns
So, the number of turns in the solenoid is 230. Hence, this is the required solution.
Answer:
2.5 m/s²
Explanation:
Acceleration: This can be defined as the rate of change of velocity.
The S.I unit of acceleration is m/s²
For circular motion, the expression for acceleration is given as,
a = ω²r ................ Equation 1
Where a = acceleration of the particle, ω = angular speed of the particle, r = radius of the circular path.
Given: ω = 5 rev/s = 31.42 rad/s, r = 0.10 m.
Substitute into equation 1
a = 5²(0.10)
a = 25(0.10)
a = 2.5 m/s²
Hence the acceleration of the particle = 2.5 m/s²
Hence, none of the option is correct
2.09sec
Add them together then divide by three because there are three numbers
<em>Answer: D</em>
<em>Given data:</em>
The electric field due to charge q₁ is (E₁) = 1.5 × 10⁵ N/C
The electric field due to charge q₂ is (E₂) = 7.2 × 10⁵ N/C
Determine the net electric field at point P (Enet) = ?
electric field measured in Newtons/coulomb
<em>We know that,</em>
The net electric field (Enet) is vector sum of E₁ and E₂ caused by the charge q₁ and q₂ respectively
Enet = E₁ + E₂
= (1.5 × 10⁵)+ (7.2 × 10⁵)
= 8.7 × 10⁵ Newtons/coulomb
<em>The net electric field at point P is 8.7 × 10⁵ N/C</em>
