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Lady_Fox [76]
3 years ago
13

How many moles of O2 are needed to react completely with 35.0 mol C2H2?

Chemistry
1 answer:
Inessa05 [86]3 years ago
6 0
2C₂H₂ + 5O₂ ---> 4CO₂ + 2H₂O
2 mol.....5 mol

2 mol C₂H₂ --- 5 mol O₂
35 mol C₂H₂ --- X mol O₂
X = (35×5)/2
X = 87,5 mol O₂
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Grasslands are a biome that receives 25-75 cm of rain each year and contain what?
s2008m [1.1K]

Answer:

<h3><em>A is most likely your correct answer</em></h3>

Explanation:

A. Hills Covered with dry brush- this is most likely correct

b. Hills covered in lush grass- incorrect, because it is LUSH grass which would require lots of rain.

c. Flat lands with little grass- incorrect because grasslands DO have lots of grass.

D- incorrect because grasslands typically do NOT have rocky mountains <u>but are generally flatlands with grass</u>

<u />

<h3>I am so sorry if this is wrong, I am just using common knowledge. TREASURE EVERY MOMENT AND HAVE AN AMAZING DAY!! ;)</h3>
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3 years ago
What advantage does a heterogeneous catalyst provide over a homogeneous catalyst in industrial processes?
irga5000 [103]
A heterogeneous catalyst can be easily separated from reactants.
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3 years ago
How are cancer cells different that normal cells
viva [34]

Answer:

I have that same photo (I always where that combo lol)

Explanation:

In contrast to normal cells, cancer cells don't stop growing and dividing, this uncontrolled cell growth results in the formation of a tumor. Cancer cells have more genetic changes compared to normal cells, however not all changes cause cancer, they may be a result of it.

7 0
3 years ago
Read 2 more answers
In an experiment, a compound was determined to contain 68.94% oxygen and 31.06% of an unknown element by weight. The molecular w
monitta

Answer is: the compound is B₂O₃.

ω(O) = 68.94% ÷ 100%.

ω(O) = 0.6894; percentage of oxygen in the compound.

ω(X) = 31.06% ÷ 100%.

ω(X) = 0.3106; percentage of unknown element in the compound.

If we take 69.7 grams of the compound:

M(compound) = 69.7 g/mol.

n(compound) = 69.7 g ÷ 69.7 g/mol.

n(compound) = 1 mol.

n(O) = (69.7 g · 0.6894) ÷ 16 g/mol.

n(O) = 3 mol.

M(compound) = n(O) · M(O) + n(X) · M(X).

n(X) = 1 mol ⇒ M(X) = 21.7 g/mol; there is no element with this molecular weight.

n(X) = 2 mol ⇒ M(X) = 10.85 g/mol; this element is boron (B).

8 0
3 years ago
which should give the most vigorous reaction when dropped in water? group of answer choices zn ca si c k
Zarrin [17]

The most vigorous reaction when dropped in water has K.

Potassium (K) is higher in activity series of metals than other metals in this question.

Activity series is an empirical progression of a series of metals, arranged by their reactivity from highest to lowest (alkaline metals have highest reactivity and Noble metals lowest reactivity).

Potassium (K) is a chemical element with atomic number 19 (number of electrons is 19).

Electron configuration of potassium is: ₁₉K 1s²2s²2p⁶3s²3p⁶4s¹.

Potassium is the alkali metal and has a single valence electron in the outer electron shell.

All alkaline metals (I group of periodic table, Na, K, Cs...) loose one electron in chemical reaction and react vigorously with water.

For more information about activity series brainly.com/question/19482695

#SPJ4

8 0
1 year ago
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