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yan [13]
2 years ago
10

Zinc bromide is considered which of the following?

Chemistry
1 answer:
OLga [1]2 years ago
5 0

Answer:

D

Explanation:

  • soluble in water and acidic
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The rock was white and black speckled with a density of 2.6 g/mL. Physical or chemical property?
stepladder [879]

Answer:

Chemical

Explanation:

7 0
3 years ago
A 2.40 kg block of ice is heated with 5820 J of heat. The specific heat of water is 4.18 J•g^-1•C^-1. By how much will it’s temp
MrMuchimi

Answer: The temperature rise is 0.53^0C

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=m\times c\times \Delta T

Q = Heat absorbed by ice = 5280 J

m = mass of ice = 2.40 kg = 2400 g   (1kg=1000g)

c = heat capacity of water = 4.18J/g^0C

Initial temperature  = T_i

Final temperature = T_f  

Change in temperature ,\Delta T=T_f-T_i=?

Putting in the values, we get:

5280J=2400g\times 4.18J/g^0C\times \Delta T

\Delta T=0.53^0C

Thus the temperature rise is 0.53^0C

0 0
3 years ago
What is true about: Na+1?
AlexFokin [52]

Hey there!

Na is sodium, which has 11 protons.

The more realistic amount of neutrons for this atom to have is 12. 23 would be the sum of protons and electrons.

The atom has a charge of 1+, so there is one less electron than protons, so

11 - 1 = 10 electrons.

Your answer is d. it has 11 protons, 10 electrons, and 12 neutrons.

Hope this helps!

6 0
2 years ago
Who has a higher frequency X-ray or, radio waves?
tester [92]

Answer:

radio waves

Explanation:

6 0
2 years ago
Chemistry Honors:
STALIN [3.7K]
In order to determine the limiting reactant, we need to obtain the number of moles of each reactant and dividing this value with the stoichiometric coefficient of the reactant. The lowest value would pertain to the limiting reactant. 

For S (32 g/mol)

number of moles of S = 5/32 = 0.15625
divide by the stoichiometric coefficient,1 = 0.15625

For H2SO4 

number of moles of H2SO4 = 0.0510
divide by the stoichiometric coefficient,2 = 0.02551

Therefore the limiting reactant is H2SO4

Mass of each product when limiting reactant is fully consumed

mass of SO2 = 0.0510 mol H2SO4 * (3 mol SO2/ 2 mol H2SO4) * (64 g SO2/ 1mol SO2) = 4.896 g

mass of H2O = 0.0510 mol H2SO4 * (2 mol H2O/ 2 mol H2SO4) * (18 g H2O/ 1 mol H2O) = 0.918 g H2O

3 0
3 years ago
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