A cord is wrapped around the outer surface of the 8-kg disk. If a force of F = (1⁄4θ²) N, where θ is in radians, is applied to the cord, determine the disk’s angular acceleration when it has turned 5 revolutions. The disc has an initial angular velocity
and radius from the center of the disc = 300 mm
Answer:
the angular acceleration = 205.706 rad/sec²
Explanation:
GIVEN THAT:
The disc mass = 8 kg
Force = 
We are told that the given θ is in radians; Therefore; the when it has turned 5 revolutions; we have the θ to be:

Also;
the initial angular velocity
radius from the center of the disc = 300 mm = 0.3 m
Thus; the mass moment about the Inertia can be determined via the following expression;



Now to calculate the angular acceleration; we equate the sum of the moments acting on the Inertia;
SO:






Hence; the angular acceleration = 205.706 rad/sec²
Answer:
2 seconds
Explanation:
Acceleration = a = -7 m/s²
u = Initial velocity = 15 m/s
v = Final velocity = 0
Distance the car will travel after hitting the brakes = s
Distance to the deer = 46 m = s₁
Time it takes the car to stop = t
From equation of motion


Maximum reaction time would be 2 seconds.
Answer:
<u />
<u />

Explanation:
Given:
- velocity of rabbit in positive x direction,

- velocity of rabbit in positive y direction,

- time taken to change the direction of velocity,

When the velocity is in x direction then the y component is zero and vice-versa.
<u>The velocity in x direction goes from </u>
<u>, therefore acceleration:</u>
<u />
<u />
<u />
<u />
<u>The velocity in y direction goes from </u>
<u>, therefore acceleration:</u>


it's broken down and eroded
Resultant vector= 24 m west.
Explanation:
resultant vector= r1+ r2 when the two vectors are in same direction
r1=10m west
r2= 14 m west
so resultant displacement= 10 + 14
resultant displacement= 24 m west