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4 years ago

6

a DJ uses a 110-volt outlet to plug in a strobe light. if the current flowing through the light is 0.050 amps, how much resistan

ce is within the circuit?

1 answer:

tigry1 [53]4 years ago

5 0

Ohms Law: V = IR

V is the voltage in volts

I is the current in amps

R is the resistance in Ohms

Rearrange: R = V/I

R = (110)/(0.050)

R = 2200

There are 2200 Ohms of resistance in the circuit.

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A cord is wrapped around the outer surface of the 8-kg disk. If a force of F = (1⁄4u2) N, where u is in radians, is applied to t

Soloha48 [4]

A cord is wrapped around the outer surface of the 8-kg disk. If a force of F = (1⁄4θ²) N, where θ is in radians, is applied to the cord, determine the disk’s angular acceleration when it has turned 5 revolutions. The disc has an initial angular velocity $\omega _o = 1 \ rad/s$ and radius from the center of the disc = 300 mm

Answer:

the angular acceleration = 205.706 rad/sec²

Explanation:

GIVEN THAT:

The disc mass = 8 kg

Force = $\dfrac{1}{4} \ \ \theta ^2* N$

We are told that the given θ is in radians; Therefore; the when it has turned 5 revolutions; we have the θ to be:

$\theta = 5 rev * (\dfrac{2 \ \pi * rad}{1 rev}) \\ \\ \theta = 10 \ \pi \ rad$

Also;

the initial angular velocity $\omega _o = 1 \ rad/s$

radius from the center of the disc = 300 mm = 0.3 m

Thus; the mass moment about the Inertia can be determined via the following expression;

$I_o = \dfrac{1}{2}*m*r^2$

$I_o = \dfrac{1}{2}*8*0.3^2$

$I_o = 0.36 \ kg/m^3$

Now to calculate the angular acceleration; we equate the sum of the moments acting on the Inertia;

SO:

$\sum M_o = I_o \alpha$

$F*0.3 = 0.36* \alpha$

$\dfrac{1}{2}* \theta^2 *0.3 = 0.36* \alpha$

$\alpha = 0.20836 \ \theta^2 \ rad/sec^2$

$\alpha = 0.20836 \ (10 \ \pi )^2 \ rad/sec^2$

$\alpha = 205.706 \ rad/sec^2$

Hence; the angular acceleration = 205.706 rad/sec²

6 0

3 years ago

A motorist traveling at 15 m/s encounters a deer in the road 46 m ahead. If the maximum acceleration the vehicle’s brakes are ca

oksian1 [2.3K]

Answer:

2 seconds

Explanation:

Acceleration = a = -7 m/s²

u = Initial velocity = 15 m/s

v = Final velocity = 0

Distance the car will travel after hitting the brakes = s

Distance to the deer = 46 m = s₁

Time it takes the car to stop = t

From equation of motion

$v^2-u^2=2as\\\Rightarrow \frac{v^2-u^2}{2a}=s\\\Rightarrow s=\frac{0^2-15^2}{2\times -7}\\\Rightarrow s=\frac{-225}{-14}=16.07\ m$

$s_1-s=u\Delta t\\\Rightarrow \Delta t=\frac{s_1-s}{u}\\\Rightarrow \Delta t=\frac{46-16.07}{15}=1.99=2\ seconds$

Maximum reaction time would be 2 seconds.

8 0

3 years ago

A rabbit is moving in the positive x-direction at 2.70 m/s when it spots a predator and accelerates to a velocity of 13.3 m/s al

avanturin [10]

Answer:

<u /> $a_x=-1.125\ m.s^{-2}$ <u />

$a_y=5.5416\ m.s^{-2}$

Explanation:

Given:

velocity of rabbit in positive x direction, $v_x=2.7\ m.s^{-1}$

velocity of rabbit in positive y direction, $v_y=13.3\ m.s^{-1}$

time taken to change the direction of velocity, $t=2.4\ s$

When the velocity is in x direction then the y component is zero and vice-versa.

<u>The velocity in x direction goes from </u> $2.7\ m.s^{-1} to\ 0\ m.s^{-1}$ <u>, therefore acceleration:</u>

<u /> $a_x=\frac{0-2.7}{2.4}$ <u />

<u /> $a_x=-1.125\ m.s^{-2}$ <u />

<u>The velocity in y direction goes from </u> $0\ m.s^{-1}\ to\ 13.3\ m.s^{-1}$ <u>, therefore acceleration:</u>

$a_y=\frac{13.3-0}{2.4}$

$a_y=5.5416\ m.s^{-2}$

6 0

3 years ago

What happens when solid rock goes through the Weathering process

Viefleur [7K]

it's broken down and eroded

8 0

4 years ago

Displacement vectors of 10 m west and 14 m west make a resultant vector that is ?

goldenfox [79]

Resultant vector= 24 m west.

Explanation:

resultant vector= r1+ r2 when the two vectors are in same direction

r1=10m west

r2= 14 m west

so resultant displacement= 10 + 14

resultant displacement= 24 m west

4 0

3 years ago