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PilotLPTM [1.2K]
3 years ago
5

Which example shows potential energy? A. a skydiver falling B. a car racing C. hitting a nail with a hammer D. a wound up watch

spring
Physics
2 answers:
goldfiish [28.3K]3 years ago
8 0
The answer is D, because all of the others show an object at work, when an object that has potential energy has to be at rest, like when you are at the top of a hill, or the highest point a rocket can go before it comes back done to the ground.
tankabanditka [31]3 years ago
6 0
B.a car racing down a hill
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A cannon is fired straight up into the air. If the cannon ball comes back down to the launch point in 5 seconds, what was the ma
Nana76 [90]

Answer:

30.63 m

Explanation:

From the question given above, the following data were obtained:

Total time (T) spent by the ball in air = 5 s

Maximum height (h) =.?

Next, we shall determine the time taken to reach the maximum height. This can be obtained as follow:

Total time (T) spent by the ball in air = 5 s

Time (t) taken to reach the maximum height =.?

T = 2t

5 = 2t

Divide both side by 2

t = 5/2

t = 2.5 s

Thus, the time (t) taken to reach the maximum height is 2.5 s

Finally, we shall determine the maximum height reached by the ball as follow:

Time (t) taken to reach the maximum height = 2.5 s

Acceleration due to gravity (g) = 9.8 m/s²

Maximum height (h) =.?

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h = ½ × 9.8 × 2.5²

h = 4.9 × 6.25

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3 0
4 years ago
During an experiment, you take a measurement of 3.5 inches. What is this
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4 0
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if a 3.1g ring is heated using 10.0 calories, its temperatures rises 17.9C calculate the specific heat capacity of the ring
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So what you do is you use the formula shown below:

specific heat capacity = energy required / (mass * change in temperature)
    
here ,
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mass (m) = 3.1g
change in temperature (ΔT) = 17.9°C    Note that "ΔT" means change in temperature

So, plugging the values into the formula, we get,

Specific heat capacity= \frac{10}{3.1*17.9}
 
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                                   = 0.1802 cal./g°C            <span>i rounded the answer to the                                                                                      fourth decimal point
</span>



6 0
3 years ago
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