Answer:
left side
Explanation:
It's smaller in length but still has a pretty close slope to the right side.
Answer:
Explanation:
The unknown charge can not remain in between the charge given because force on the middle charge will act in the same direction due to both the remaining charges.
So the unknown charge is somewhere on negative side of x axis . Its charge will be negative . Let it be - Q and let it be at distance - x on x axis.
force on it due to rest of the charges will be equal and opposite so
k3q Q / x² =k 8q Q / (L+x)²
8x² = 3 (L+x)²
2√2 x = √3 (L+x)
2√2 x - √3 x = √3 L
x(2√2 - √3 ) = √3 L
x = √3 L / (2√2 - √3 )
Let us consider the balancing force on 3q
force on it due to -Q and -8q will be equal
kQ . 3q / x² = k3q 8q / L²
Q = 8q (x² / L²)
so charge required = - 8q (x² / L²)
and its distance from x on negative x side = √3 L / (2√2 - √3 )
Momentum in x-axis before collision: 4.5 x 1.5 = 6.75
Momentum in x-axis after collision: 1.5 x 2.1 x cos(30) + 3.2 x v x cos(30)
By the principle of conservation of momentum, these are equal:
6.75 = 2.73 + 2.77v
v = 1.45 m/s
Ok to distinguish the difference you just find out why there's science lol.......anyways.....Mass is the amount of space being taken up in a certain place (or possibly all the world) and weight is the heaviness of an person or thing kk??? also if my answer was best, plzz give brainliest (trust me i need it) Have a great day and Christmas (if u celebrate it)!!
(a) The angular speed of the system at the instant the beads reach the end of the rod is 9.26 rad/s.
(b) The angular speed of the rod after the after the beads fly off the rod's ends is 25.71 rad/s.
<h3>Moment of inertia through the center of the rod</h3>
I = ¹/₁₂ML²
I = ¹/₁₂ (0.1)(0.5)²
I = 0.0021 kgm²
For the beads, I = 2Mr² = 2(0.03 x 0.1²) = 0.0006 kgm²
Total initial moment of inertia, Ii = 0.0021 kgm² + 0.0006 kgm²
I(i)= 0.0027 kgm²
When the beads reach the end, I = 2Mr² = 2(0.03)(0.25)² = 0.00373 kgm²
Total final moment of inertia, I(f) = 0.0021 kgm² + 0.00373 kgm²
I(f) = 0.00583 kgm²
<h3>Speed of the system</h3>
The speed of the system at the moment the beads reach the end of the rod is calculated as follows;
<h3>Speed of the rod when the beads fly off</h3>
Learn more about moment of inertia of rods here: brainly.com/question/3406242