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Angelina_Jolie [31]
3 years ago
12

PLEASE HELP!

Physics
2 answers:
tino4ka555 [31]3 years ago
8 0

Answer:

option (c)

Explanation:

A small diameter open tube is called capillary tube.

When a capillary tube is immersed in a vessel containing mercury, then the mercury falls in the capillary tube and the shape is like outside of an umbrella.  

As the angle of contact for mercury and glass is obtuse, so it falls in the tube and the meniscus is convex.

maks197457 [2]3 years ago
4 0
The answer is A .
Due to air pressure, the mercury in the tube will be higher than that in the vessel.
Mercury in a container, the center of the liquid is always higher, so it is shaped like the outside of an umbrella.
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Answer:

10N

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1. Every Action has an equal and opposite reAction.

2. If 10N of force is acted upon an wrench, then the wrench will react with an equal amount of force, but in the opposite direction.

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Can black wholes be an exit to the universe,why or why not? (just curious).
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As a pole of a 2nd-order discrete-time system moves away from the origin in the z-plane, while its phase remains constant, the d
Rudik [331]

Answer:

False

Explanation:

When the location of the poles changes in the z-plane, the natural or resonant frequency (ω₀) changes which in turn changes the damped frequency (ωd) of the system.

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4 0
3 years ago
If the net external force acting on a system is zero , then the total momentum of the system is zero
Neporo4naja [7]
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8 0
4 years ago
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When 597 J of heat are added to a gas, it expands. Its internal energy increases by 318 J. How much work does the gas do? (Unit=
damaskus [11]

The magnitude of work done by the gas is 279 J and the sign is negative so W = -279 J as work is done by the system.

<u>Explanation:</u>

According to first law of thermodynamics, the change in internal energy of the system is equal to the sum of the heat energy added or released from the system with the work done on or by the system. If the heat energy is added to the system to perform a certain work, then the heat energy is taken as positive, while it will be negative when the heat energy is released from the system.

Similarly, in this case, the heat energy of 597 J is added to the system. So the heat energy will be positive, while the gas expansion occurs means work is done by the system.

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Since ΔU is the change in internal energy which is given as 318 J and the heat energy added to the system is Q = 597 J.

Then the work done by the gas = ΔU - Q = 318 J - 597 J = - 279 J.

As the work is done by the system, so it will be denoted in negative sign and the magnitude of work done by the gas is 279 J.

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3 years ago
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