The answer:
<span>When the elevator accelerates upward at a rate of 3.6 m/s², the value of the acceleration becomes
</span>A=g+3.6=13.4 m/s²
and by using the newton's law, F=mass x A, we have
T1= (24 + 90 )x 13.4= 1527.6 N, where T1 is the <span>Tension in upper rope
</span> and
T2= ( 90 )x 13.4= 1206N, where T2 is the Tension in lower rope
When the elevator accelerates downward at a rate of 3.6 m/s², the value of the acceleration becomes
A=9.8 - 3.6 = 6.2 m/s²
T1= (24 + 90 )x 6.2= 706.8 N, where T1 is the Tension in upper rope
and
T2= ( 90 )x 6.2= 558N, where T2 is the Tension in lower rope
Impulse<span> is the change of momentum of an object when the object is acted upon by a force for an interval of time. It is simply calculated by the expression:
</span>
Impulse = F(change in time)
Impulse = 60(2)
Impulse = 120 Ns
Hope this answers the question. Have a nice day.
Answer: (a)part:545nm multiply by 0.440m=239.8JEWELS(J)
(B):1/2MULTIPLY BY MVSQUARE(APPLY THE FORMULA OF KINETIC ENERGY)REARANGE THE FORMULA,V=2.13MS
Explanation:
SO FOR PART A, IN ORDER TO CALCULATE THE WORK DONE YOUR SUPPOSE TO APPLY THE FORMULA FORCE MULTIPLY BY DISTANCE WHICH IS THE FORMULA FOR WORK DONE,IN THIS SCENARIO YOU HAD A FORCE OF 545NM AND A DISANCE OF 0.440,SO I ORDER TO FIND THE WORK DONE WE MULTIPLIED THEM BOTHE ACCORDING TO THE FORMULA AND GOT THE ANSWER.
FOR PARTB,I JUST SIMPLY APPLIED THE FORMULA FOR KINETIC ENERGY AND SIMPLY REARRANGED IT IN ORDER TO FIND THE VELOCITY.I MADE V THE SUBJECT OF THE FORMULA.
Correct Answer:
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Concept:
Wave: It is the disturbance in which the energy is transferred from one place to another place. During the propagation of the wave, medium particles do not move. They vibrate at their position in to and fro form.
In case of the Transverse wave, medium particles vibrate perpendicular to the direction of the wave while in case of Longitudinal wave, they vibrate along the direction of the wave.
Hence, the best definition of the wave will be the disturbance that transfers the energy from one place to another place.