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Snezhnost [94]
3 years ago
9

Recall the observed behavior of the compass during the mapping of the magnetic field. Which of the following descriptions best m

atches the behavior you observed? Two correct answers required for full credit.
A. Where the field is strong the compass needle readily and quickly aligns with rapid oscillations around the equilibrium direction.
B. Where the field is strong the compass needle slowly oscillates around the final equilibrium position.
C. Where the field is weak the compass needle rapidly oscillates around the final equilibrium position.
D. Where the field is weak the compass needle slowly oscillates around the final equilibrium position.
E. Where the field is weak the compass needle readily and quickly aligns with rapid oscillations around the equilibrium direction.
Physics
1 answer:
Vlad [161]3 years ago
7 0

Answer:

Option A & B

Explanation:

This is cause the compass needle is magnetized anointed in such a way that it responds to magnetic field strength.

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Answer:A

Explanation:

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3 years ago
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calculate how much charge passes through the LED in 1 hour if the current flowing in the circuit below is 350mA
Morgarella [4.7K]

Given the the current flowing in the circuit and the elapsed time, the charge that passes through the LED is 1260 Coulombs.

<h3>What is Current?</h3>

Current is simply the rate of flow of charged particles i.e electrons caused by EMF or voltage.

If a charge passes through the cross-section of a conductor in a given time, the current I is expressed as;

I = Q/t

Where Q is the charge and t is time elapsed.

Given the data in the question;

  • Time elapsed t = 1hr = 3600s
  • Current I = 350mA = 0.35A
  • Charge Q = ?

We substitute our given values into the expression above to determine the charge.

I = Q/t

Q = I × t

Q = 0.35A × 3600s

Q = 1260C

Therefore,  given the the current flowing in the circuit and the elapsed time, the charge that passes through the LED is 1260 Coulombs.

Learn more about current here: brainly.com/question/3192435

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3 0
2 years ago
Sam, whose mass is 75 kg, straps on his skis and starts down a 50-m-high, 20 frictionless slope. A strong headwind exerts a hori
LenaWriter [7]

Answer:

Explanation:

Sam mass=75kg

Height is 50m

20° frictionless slope

Horizontal force on Sam is 200N

According to the work energy theorem, the net work done on Sam will be equal to his change in kinetic energy.

Therefore

Wg - Ww =∆K.E

Note initial the body was at rest at top of the slope.

Then, ∆K.E is K.E(final) - K.E(initial)

K.E Is given as ½mv²

Since initial velocity is zero then, K.E(initial ) is zero

Therefore, ∆K.E=½mVf²

Wg is work done by gravity and it is given by using P.E formulas

Wg=mgh

Wg=75×9.8×50

Wg=36750J

Ww is work done by wind and it's is given by using formulae for work

Work=force × distance

Ww=horizontal force × horizontal distance

Using Trig.

TanX=opposite/adjacent

Tan20=h/x

x=h/tan20

x=50/tan20

x=137.37m

Then,

Ww=F×x

Ww=200×137.37

We=27474J

Now applying the formula

Wg - Ww =∆K.E

36750 - 27474 =½×75×Vf²

9276=37.5Vf²

Vf²=9275/37.5

Vf²= 247.36

Vf=√247.36

Vf=15.73m/s

3 0
4 years ago
Through which one of the following mediums is the velocity of a sound wave the greatest?
Colt1911 [192]

Answer: <u><em>C. Steel</em></u>

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<em><u>of an elastic material, the velocity of the wave is relatively</u></em>

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<em><u>high. For instance, the velocity of a sound wave traveling</u></em>

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<em><u>through steel (which is almost perfectly elastic) is about</u></em>

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<em><u>5,060 meters per second. On the other hand, the velocity</u></em>

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<em><u>of a sound wave traveling through an inelastic solid is</u></em>

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<em><u>relatively low. So, for example, the velocity of a sound wave</u></em>

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<em><u>traveling through lead (which is inelastic) is approximately</u></em>

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<em><u>1,402 meters per second.</u></em>

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6 0
3 years ago
An engineer is investigating energy loss through windows. The windowpane of interest is 0.650 cm thick, has dimensions of 1.19 m
krok68 [10]

Answer:

7908.92307 W

683330953.248 J

Explanation:

k = Heat conduction coefficient = 0.8 W/(m·°C)

A = Area = 1.19\times 2.25\ m^2

l = Thickness = 0.65 cm

T_2 = 24°C

T_1 = 0°C

Rate of heat transfer is given by

Q=\frac{kA(T_2-T_1)}{l}\\\Rightarrow Q=\frac{0.8\times 1.19\times 2.25(24-0)}{0.65\times 10^{-2}}\\\Rightarrow Q=7908.92307\ W

The rate of heat transfer is 7908.92307 W

Amount of energy is given by

E=Qt\\\Rightarrow E=7908.92307\times 24\times 3600\\\Rightarrow E=683330953.248\ J

The energy transferred through the window in one day is 683330953.248 J

8 0
3 years ago
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