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evablogger [386]
3 years ago
9

How do you draw the structure of methylcyclohexane?

Chemistry
1 answer:
Mekhanik [1.2K]3 years ago
3 0

<u>Methylcyclohexane:</u>

The chemical formula of the organic compound, methylcyclohexane is \mathrm{CH}_{3} \mathrm{C}_{6} \mathrm{H}_{11}. It is branched into the group of saturated hydrocarbon.

Note: Refer the attached image for the structure of methylcyclohexane

<u>Structure of methylcyclohexane:</u>

  • It is a monosubstituted cyclohexane because it has one branching through the attachment of single methyl group on one carbon of the cyclohexane ring.
  • Being very toxic to the aquatic ecosystem, the methyl group of this compond in its axial position experiences a steric strain or steric crowding.

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If you start with 14.0 grams of diatomic nitrogen (N2) how many grams of diatomic hydrogen (H2) will react with it?
irinina [24]

Answer:

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Explanation:

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7 0
3 years ago
What volume of CH4(g), measured at 25oC and 745 Torr, must be burned in excess oxygen to release 1.00 x 106 kJ of heat to the su
anastassius [24]

Answer:

V=27992L=28.00m^3

Explanation:

Hello,

In this case, the combustion of methane is shown below:

CH_4+2O_2\rightarrow CO_2+2H_2O

And has a heat of combustion of −890.8 kJ/mol, for which the burnt moles are:

n_{CH_4}=\frac{-1.00x10^6kJ}{-890.8kJ/mol}= 1122.6molCH_4

Whereas is consider the total released heat to the surroundings (negative as it is exiting heat) and the aforementioned heat of combustion. Then, by using the ideal gas equation, we are able to compute the volume at 25 °C (298K) and 745 torr (0.98 atm) that must be measured:

PV=nRT\\\\V=\frac{nRT}{P}=\frac{1122.6mol*0.082\frac{atm*L}{mol*K}*298K}{0.98atm}\\\\V=27992L=28.00m^3

Best regards.

8 0
4 years ago
The compounds n-butane, ch3(ch2)2ch3, and trimethylamine, n(ch3)3, have very similar molecular weights. However, their melting p
Ostrovityanka [42]
<h3>Answer:</h3>

            The lowest boiling point is of n-Butane because it only experiences London Dispersion Forces between molecules.

<h3>Explanation:</h3>

                   Lets take start with the melting point of both compounds.

                                      n-Butane  =  - 140 °C

                                      Trimethylamine  =  - 117 °C

Intermolecular Forces in n-Butane:

                                                      As we know n-Butane is made up of Carbon and Hydrogen atoms only bonded via single covalent bonds. The electronegativity difference between C and C atoms is zero while, that between C and H atoms is 0.35 which is less than 0.4. Hence, the bonds in n-Butane are purely non polar in nature. Therefore, only London Dispersion Forces are found in n-Butane which are considered as the weakest intermolecular interactions.

Intermolecular Forces in Trimethylamine:

                                                             Trimethylamine (a tertiary amine) is made up of Nitrogen, Carbon and Hydrogen atoms bonded via single covalent bonds. The electronegativity difference between N and C atoms is 0.49  which is greater than 0.4. Hence, the C-N bond is polar in nature. Therefore, Dipole-Dipole interactions will be formed along with London Dispersion Forces which are stronger than Dispersion Forces. Therefore, due to Dipole-Dipole interactions Trimethylamine will have greater melting point than n-Butane.

5 0
4 years ago
How many minutes will it take to plate out 2.19 g of chromium metal from a solution of Cr3+Cr3+ using a current of 55.2 amps in
Kamila [148]

Answer : The time it take to plate out will be, 3.69 minutes.

Explanation :

First we have to calculate the moles of Cr.

\text{Moles of }Cr}=\frac{\text{Mass of Cr}}{\text{Molar mass of Cr}}

Molar mass of Cr = 51.9 g/mol

\text{Moles of }Cr}=\frac{2.19g}{51.9g/mol}=0.0423mol

The cathode half-reaction is,

Cr^{3+}+3e^-\rightarrow Cr

From this we conclude that,

The number of electrons (n)  in the reaction are 3.

The quantity of charge required for the reduction of 1 mole of Cr^{3+} = 3\times F

The quantity of charge required for the reduction of 0.0423 mole of Cr^{3+} = 0.0423\times 3\times F=0.1269F=0.1269\times 96500C=12245.85C

Now we have to calculate the time taken.

We know that,

q=I\times t

t=\frac{q}{I}=\frac{12245.85C}{55.2A}=221.845s=3.69min

Thus, the time it take to plate out will be, 3.69 minutes.

7 0
3 years ago
2. What is the mass of one mole of Na?
borishaifa [10]
Sodium, Atomic mass: 22.989769 g
You can see in a periodic table
5 0
3 years ago
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