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serious [3.7K]
3 years ago
9

Which is the incorrect association between monomer and polymer? nucleotide - nucleic acid amino acid - polypeptide monosaccharid

e - polysaccharide nucleic acid - polypeptide?
Chemistry
1 answer:
maks197457 [2]3 years ago
5 0

Option 4 is right option regarding incorrect association.

A nucleotide is a monomer made of sugar, base and phosphate group whereas nucleic acid is a polymer of nucleotide. Thus, this association is correct.

Amino acid is a monomer such as glycine, alanine whereas polypeptide made from association of number of amino acid by creating a peptide linkage to produce a polypeptide.

Monosaccharide is a monomer such as glucose, fructose which associates together to produce polysaccharide such as cellulose made from glucose.

nucleic acid is a polymer of nucleotide whereas polypeptide made from association of number of amino acid by creating a peptide linkage to produce a polypeptide.

Thus, option 4 is right option having incorrect association.


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3. Given the Lewis electron-dot diagram:
madam [21]

Answer:

1) the carbon and hydrogen valence electrons

Explanation:

The lewis dot diagram illustrates how electrons are arranged round atoms in a molecule. The dots represents the;

1) the carbon and hydrogen valence electrons

4 0
3 years ago
An equilibrium mixture of CO, O2 and CO2 at a certain temperature contains 0.0010 M CO2 and 0.0025 M O2. At this temperature, Kc
pantera1 [17]

Answer:

5.35 *10^{-4}M

Explanation:

Equation for the reaction is as follows:

2CO_{(g)}      +      O_{2(g)}        ⇄       2CO_{2(g)}

By Applying the ICE Table; we have

                             2CO_{(g)}      +      O_{2(g)}        ⇄       2CO_{2(g)}

Initial                      x                  0.0025 M              0.0010 M

Change                  0                       0                            0

Equilibrium             x                  0.0025 M              0.0010 M

K_c =\frac{[CO_2]^2}{[CO]^2[O_2]}

Given that K_c = 1.4*10^2 ; Then:

1.4 *10^2 = \frac{(0.001)^2}{(x)^2(0.025)}

1.4 *10^2*0.025 = \frac{(0.001)^2}{(x)^2}

3.5 =( \frac{(0.001)}{(x)})^2

\sqrt {3.5} = \sqrt {( \frac{(0.001)}{(x)} )^2}

1.87=\frac{(0.001)}{(x)}

(x)= \frac{(0.001)}{1.87 }

x = 5.35 *10^{-4}M

∴ The equilibrium concentration of CO = x = 5.35 *10^{-4}M

7 0
3 years ago
I need someones help
valentinak56 [21]

Answer:

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3 0
2 years ago
What is the main component of atoms that determines the type of bond that forms between atoms or compounds? Explain.
goldenfox [79]
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4 0
3 years ago
How many moles of MgCl2 where needed to make a 650.0 mL solution a concentration of 0.962 M?
Murljashka [212]

Answer:

0.625 moles MgCl₂

Explanation:

Since you were given a molarity value and volume, you should use the molarity equation to find moles. The equation looks like this:

Molarity (M) = moles / volume (L)

To find moles, you need to (1) convert mL to L (by dividing by 1,000) and then (2) plug the numbers into the formula and simplify to find moles. The final answer should have 3 sig figs as the lowest amount of sig figs in a given value is 3.

<u>Step 1:</u>

650.0 mL / 1,000 = 0.6500 L

<u>Step 2:</u>

Molarity = moles / volume

0.962 M = moles / 0.6500 L

(0.962 M) x (0.6500 L) = moles

0.625 = moles

5 0
2 years ago
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