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Anettt [7]
3 years ago
14

Fe + CuSO4 Cu + Fe2(SO4)3 is a balanced equation for the redox reaction true false

Chemistry
2 answers:
natulia [17]3 years ago
6 0

Answer:

False.

Explanation:

The balanced equation is:

2Fe + 3CuSO4 ----> 3Cu + Fe2(SO4)^3

exis [7]3 years ago
3 0

Answer:

False. The balance equation for the redox reaction is:

2Fe  + 3CuSO₄ → 3Cu + Fe₂(SO₄)₃

Explanation:

Let's think the half reactions:

Fe → Fe³⁺  +  3e⁻

The Fe increase the oxidation state. This is the oxidation, where Fe changes from 0 to +3

Cu²⁺  + 2e⁻ → Cu

This is the reduction. Cu changes from 2+ to 0

We multiply the half reaction x2 and x3 to balance the electrons

2Fe → 2Fe³⁺  +  6e⁻

3Cu²⁺  + 3e⁻ → 3Cu

And we sum both

2Fe  + 3Cu²⁺  + 6e⁻ → 3Cu + 2Fe³⁺  +  6e⁻

The electrons are cancelled, so the balance reaction is:

2Fe  + 3CuSO₄ → 3Cu + Fe₂(SO₄)₃

 

You might be interested in
What is the orbital hybridization of a central atom that has one lone pair and bonds to:
svlad2 [7]

sp^3d is the type of orbital hybridization of a central atom that has one lone pair and bonds to four other atoms.

<h3>What is orbital hybridization?</h3>

In the context of valence bond theory, orbital hybridization (or hybridisation) refers to the idea of combining atomic orbitals to create new hybrid orbitals (with energies, forms, etc., distinct from the component atomic orbitals) suited for the pairing of electrons to form chemical bonds.

For instance, the valence-shell s orbital joins with three valence-shell p orbitals to generate four equivalent sp3 mixes that are arranged in a tetrahedral configuration around the carbon atom to connect to four distinct atoms.

Hybrid orbitals are symmetrically arranged in space and are helpful in the explanation of molecular geometry and atomic bonding characteristics. Usually, atomic orbitals with similar energies are combined to form hybrid orbitals.

Learn more about hybridization

brainly.com/question/22765530

#SPJ4

5 0
2 years ago
Using the graph below please draw a reaction potential energy diagram for a reaction with the
azamat

Answer:

12

Explanation:

because it is the sam

7 0
3 years ago
What is the concentration of a solution which is 2g in 150cm3 in g/dm3
Irina-Kira [14]

Answer:

13.33 g/dm³

Explanation:

Concentration (g/dm³)= mass(g) ÷ volume (dm³)

Now you need to convert 150 cm³ to dm³

1000cm³ = 1 dm³

thus, 150 cm3= 150 ÷ 1000

= 15dm³

and you already have mass in grams

so concentration  = 2 ÷ 0.15

= 13.33 g/dm³ and there you go.. solved ;)

8 0
3 years ago
Rank the following fertilizers in decreasing order of mass percentage of nitrogen:
charle [14.2K]
<h3>Answer:</h3>

        NH₃ > NH₄NO₃ > (NH₄)₂HPO₄ > (NH₄)₂SO₄ > KNO₃ > (NH₄)H₂PO₄

<h3>Soution:</h3>

In (NH₄)₂HPO₄:

Mass of Nitrogen  =  N × 2  =  14 × 2  =  28 g.mol⁻¹

Molar Mass of (NH₄)₂HPO₄  =  132.06 g.mol⁻¹

Mass %age  =  Mass of N / M.Mass of (NH₄)₂HPO₄ × 100

Mass %age  =  28 g.mol⁻¹ / 132.06 g.mol⁻¹ × 100

Mass %age  =  21.20 %

In (NH₄)₂SO₄:

Mass of Nitrogen  =  N × 2  =  14 × 2  =  28 g.mol⁻¹

Molar Mass of (NH₄)₂SO₄  =  132.14 g.mol⁻¹

Mass %age  =  Mass of N / M.Mass of (NH₄)₂SO₄ × 100

Mass %age  =  28 g.mol⁻¹ / 132.14 g.mol⁻¹ × 100

Mass %age  =  21.18 %

In KNO₃:

Mass of Nitrogen  =  N × 1  =  14 × 1  =  14 g.mol⁻¹

Molar Mass of KNO₃  =  101.10 g.mol⁻¹

Mass %age  =  Mass of N / M.Mass of KNO₃ × 100

Mass %age  =  14 g.mol⁻¹ / 101.10 g.mol⁻¹ × 100

Mass %age  =  13.84 %

In (NH₄)H₂PO₄:

Mass of Nitrogen  =  N × 1  =  14 × 1  =  14 g.mol⁻¹

Molar Mass of (NH₄)H₂PO₄  =  115.03 g.mol⁻¹

Mass %age  =  Mass of N / M.Mass of (NH₄)H₂PO₄ × 100

Mass %age  =  14 g.mol⁻¹ / 115.03 g.mol⁻¹ × 100

Mass %age  =  12.17 %

In NH₃:

Mass of Nitrogen  =  N × 1  =  14 × 1  =  14 g.mol⁻¹

Molar Mass of NH₃  =  132.14 g.mol⁻¹

Mass %age  =  Mass of N / M.Mass of NH₃ × 100

Mass %age  =  14 g.mol⁻¹ / 17.03 g.mol⁻¹ × 100

Mass %age  =  82.20 %

In NH₄NO₃:

Mass of Nitrogen  =  N × 2  =  14 × 2  =  28 g.mol⁻¹

Molar Mass of NH₄NO₃  =  80.04 g.mol⁻¹

Mass %age  =  Mass of N / M.Mass of NH₄NO₃ × 100

Mass %age  =  28 g.mol⁻¹ / 80.04 g.mol⁻¹ × 100

Mass %age  =  34.98 %

5 0
3 years ago
How many grams of oxygen are produced when 7.65 moles of water is decomposed
maksim [4K]

Answer:

The answer to your question is 122.4 g of O₂

Explanation:

Data

mass of O₂ = ?

moles of H₂O = 7.65

Process

1.- Write the balanced chemical reaction

                   2H₂O  ⇒  2H₂  +  O₂

2.- Convert the moles of H₂O to grams

molar mass of H₂O = 2 + 16 = 18 g

                    18 g of H₂O ---------------- 1 mol

                      x                ----------------- 7.65 moles

                      x = (7.65 x 18) / 1

                      x = 137.7 g H₂O

3.- Calculate the grams of O₂

                 36 g of H₂O -------------------- 32 g of O₂

              137.7 g of H₂O -------------------  x

                        x = (32 x 137.7) / 36

                       x = 122.4 g of O₂

 

6 0
3 years ago
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