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Kitty [74]
3 years ago
7

Advantages, disadvantages and applications of dsb-sc​

Engineering
1 answer:
allochka39001 [22]3 years ago
3 0

Answer:

<h3>advantages: </h3>

<em>lower power consumption, modulation system is simple</em>

<h3>disadvantages<em>:</em></h3>

<em>complex detection</em>

<h3><em>applications:</em></h3>

analog TV systems: to transmit color information

<h3><em /></h3>

<em />

<em />

<em />

<em />

Explanation:

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A centrifugal pump is required to pump water to an open water link situated 4 km away from the location of the pump through a pi
11111nata11111 [884]

Answer:

P= 5.5 bar

Explanation:

Given that

L= 4000 m

d= 0.2 m

Friction factor(F) = 0.01

speed V= 2 m/s

Head = 5 m

Head loss due to friction

h_f=\dfrac{FLV^2}{2gd}

h_f=\dfrac{0.01\times 4000\times 2^2}{2\times 9.81\times 0.2}

h_f=40.77m

So the total head(H) = 5 + 40.77 + 10.3 =56.07

Where 10.3 m is the atmospheric head.

We know that

P=ρ g H

So total Pressure

P= 1000 x 9.81 x 56.07 Pa

P=5.5\times 10^5\ Pa

P= 5.5 bar

5 0
3 years ago
Match the terms with the correct definitions.
arsen [322]
I think answer should be the first one please give me brainlest let me know if it’s correct or not okay thanks bye
7 0
2 years ago
A PMMA plate with a 25 mm (width) x 6.5 mm (thickness) cross-section has a contained crack of length 2c = 0.5 mm in the center o
victus00 [196]

Answer:

LAOD = 6669.86 N

Explanation:

Given data:

width= 25 mm = 25\times 10^{-3} m

thickness = 6.5 mm = 6.5\times 10^{-3} m

crack length 2c = 0.5 mm at centre of specimen

\sigma _{applied} =  1000 N/cross sectional area

stress intensity factor  =  k  will be

\sigma_{applied} = \frac{1000}{25\times 10^{-3}\times 6.5\times 10^{-3}}

                   = 6.154\times 10^{6} Pa

we know that

k =\sigma_{applied} (\sqrt{\pi C})

  =6.154\sqrt{\pi (2.5\times 10^{-04})}          [c =0.5/2 = 2.5*10^{-4}]

K = 0.1724 Mpa m^{1/2} for 1000 load

ifK_C = 1.15 Mpa m^{1/2} then load will be

Kc = \sigma _{frac}(\sqrt{\pi C})

1.15 MPa = \sigma _{frac}\times \sqrt{\pi (2.5\times 10^{-04})}

\sigma _{frac} = 41.04 MPa

load = \sigma _{frac}\times Area

load = 41.04 \times 10^6 \times 25\times 10^{-3}\times 6.5\times 10^{-3} N

LAOD = 6669.86 N

3 0
2 years ago
Which is equal to a temperature of 50°F?<br><br> 18°C<br> 46°C<br> 10°C<br> 32°C
Ludmilka [50]

Answer:

10°C degrees po ang sagot

8 0
3 years ago
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Which claim does president Kennedy make in speech university rice ?
mafiozo [28]

Answer:  The United States must lead the space race to prevent future wars.

Explanation: Hope this helps

4 0
2 years ago
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