A ball is dropped off a very tall canyon ledge. Gravity accelerates the ball at 9.8 m/s2. How fast is the ball traveling after 5
1 answer:
As ball is dropped, so its initial velocity (u) of the ball is = 0
Acceleration of the ball (a) is given to be 9.8 m/s^2
As acceleration is constant, so we can apply the equation of kinematics for constant acceleration i.e.
where u is initial velocity, a is acceleration and v is final velocity at after time t
so velocity after 5 sec will be
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Explanation:
1. Force applied on an object is given by :
F = W = mg
(a) A 160 lb human being, F = 160 lb
g = acceleration due to gravity, g = 32 ft/s²
m = 5 kg
(b) A 1.9 lb cockatoo, F = 1.9 lb
m = 0.059 kg
2. (a) A 2300 kg rhinoceros, m = 2300 kg
(b) A 22 g song sparrow, m = 22 g = 0.022 kg
Hence, this is the required solution.