A ball is dropped off a very tall canyon ledge. Gravity accelerates the ball at 9.8 m/s2. How fast is the ball traveling after 5
1 answer:
As ball is dropped, so its initial velocity (u) of the ball is = 0
Acceleration of the ball (a) is given to be 9.8 m/s^2
As acceleration is constant, so we can apply the equation of kinematics for constant acceleration i.e.
where u is initial velocity, a is acceleration and v is final velocity at after time t
so velocity after 5 sec will be
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Answer:
(C) Decreases by factor of 3
Explanation:
Centripetal acceleration is given by
where <em>v</em> is the linear velocity and <em>r</em> is the radius of the curve.
Let the centripetal acceleration on the curve of radius <em>R</em> be .
Then
Let the centripetal acceleration on the curve of radius 3<em>R</em> be .
Then
Here, we see that the acceleration decreases by a factor of 3.