A ball is dropped off a very tall canyon ledge. Gravity accelerates the ball at 9.8 m/s2. How fast is the ball traveling after 5
1 answer:
As ball is dropped, so its initial velocity (u) of the ball is = 0
Acceleration of the ball (a) is given to be 9.8 m/s^2
As acceleration is constant, so we can apply the equation of kinematics for constant acceleration i.e.
where u is initial velocity, a is acceleration and v is final velocity at after time t
so velocity after 5 sec will be
You might be interested in
Answer:
<u>Explanation:</u>
A linear equation is of the form: y = mx + b where
- m is the slope
- b is the y-intercept (where it crosses the y-axis)
x + 4y = 16
4y = -x + 16
The y-intercept (b) = 4
Next, find the slope given point (4, 5) and b = 4
Answer:
Explanation:
The period of a simple pendulum is given by:
where
L is the length of the pendulum
g is the acceleration of gravity
From this equation we can write
Taking the square of this equation, we get:
So we see that is proportional to L and inversely proportional to g. So, we can write:
So the only correct option is