As ball is dropped, so its initial velocity (u) of the ball is = 0
Acceleration of the ball (a) is given to be 9.8 m/s^2
As acceleration is constant, so we can apply the equation of kinematics for constant acceleration i.e.
where u is initial velocity, a is acceleration and v is final velocity at after time t
so velocity after 5 sec will be
Explanation:
Below is an attachment containing the solution.
The current passing through a circuit consisting of a battery of 12 V and resistor of 2 ohms is 6 Ampere .
I = V/R = 12/2 = 6.000 A.