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2 years ago

I WILL GIVE BRAINLIEST!!!!!!!!

Chemistry

2 answers:

Crazy boy [7]2 years ago

7 0

0.92 HCI i think. vote 5

musickatia [10]2 years ago

3 0

Molarity = moles / Liters

1) moles of NaOH: Molarity * Liters = .1250M * .044L = .0055 moles NaOH

2) NaOH and HCl are both strong acid/base so they 100% dissociate and at the end point, you have the same # of moles of HCl as NaOH. --> .0055 moles HCl

<span> 3) M = .0055 mol / (.01 + .05)L = .092M HCl

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In a balanced chemical reaction, the number of atoms of each element in the product(s) always equals the

dangina [55]

A ? Or c I thinkkkkkk

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2 years ago

Read 2 more answers

Part 1. A chemist reacted 18.0 liters of F2 gas with NaCl in the laboratory to form Cl2 gas and NaF. Use the ideal gas law equat

Alika [10]

Answer:

Part 1

The mass of the NaCl that reacted with F₂ at 290.K and 1.5 atm is approximately 132.6 gams

Part 2

The mass of NaCl that can react with the same volume of gas at STP is approximately 93.77 grams

Explanation:

Part 1

The volume of F₂ gas in the reaction, V = 18.0 liters

The ideal gas equation is P·V = n·R·T

∴ n = P·V/(R·T)

The pressure, P = 1.5 atm

The temperature, T = 290 K

The universal gas constant, R = 0.0820573 L·atm/(mol·K)

∴ n = 1.5×18/(0.0820573 × 290) ≈ 1.134615

The number of moles of F₂ in the reaction n ≈ 1.134615 moles

The chemical reaction is given as follows;

F₂ + 2NaCl → Cl₂ + 2NaF

1 mole of F₂ reacts with 2 moles of NaCl

Therefore;

1.134615 moles of F₂ reacted with 2 × 1.134615 moles ≈ 2.26923 moles of NaCl

1 mole of NaCl = The molar mass of NaCl, MM = 58.44 g/mol

The mass, of 2.26923 moles of NaCl, m = Number of moles × MM

∴ m ≈ 2.26923 moles × 58.44 g/mol ≈ 132.6 grams

The mass of the NaCl ≈ 132.6 gams

Part 2

The volume occupied by 1 mole of all gases at STP = 22.4 l/mole

Therefore, the number of moles of F₂ in 18.0 L of F₂ = 18.0 L/(22.4 L/mole) ≈ 0.804 moles

Therefore;

The number of moles of NaCl, in the reaction n = 2 × The number of moles of F₂ ≈ 2×0.804 moles = 1.608 moles

The number of moles of NaCl, in the reaction n ≈ 1.608 moles

The mass of NaCl in the reaction, m = n × MM

∴ m ≈ 1.608 moles × 58.44 g/mol ≈ 93.97 grams

The mass of NaCl that can react with the same volume of gas at STP ≈ 93.77 grams

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3 years ago

Another example of a parasitic

sasho [114]

Answer:a leech

Explanation: a parasitic relationship is one organism benefit on the other while the other is harmed

7 0

3 years ago

Hi, can someone help me balance this chemistry equation:<br> H2SO4 + RbOH -> Rb2SO4 + H2O

zloy xaker [14]

H2SO4 + 2RbOH -> Rb2SO4 + 2H2O

If you want an explanation, keep reading.

In the first portion, there are two hydrogen ions and four sulfate ions.

The second portion has one rubidium ions and one hydroxide ion.

On the other side of the equation, in order to keep those two rubidiums balanced, you'll need to add a two at the beginning of the second portion, but in that process you are giving a second hydroxide value.

Back to the right side, there is there is water (H2O).

On the first portion, there were two hydrogen ions. The second portion also has two hydroxides because of the value change (adding the two to the front).

So on the fourth portion, you'd have to add another two so you could balance the four hydrogen ions (H2 and 2OH) and the two oxygen ions (2OH).

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3 years ago

If 250 milliliters of Calcium Hydroxide is titrated with 345 milliliters of 0.75 molarity hydrobromic acid, what is the concentr

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The balanced neutralization reaction here is:

Ca(OH)2 + 2HBr --> 2H2O + CaBr2

Notice that two moles of Her are required to neutralize every one mole of Ca(OH)2. This means that for however many moles of Her reacted, HALF as many moles of Ca(OH)2 reacted as well.

Moles of HBr reacted = 0.75 M x 0.345 L = 0.259 mol

Moles of Ca(OH)2 reacted = 0.259 mol / 2 = 0.130 mol

Concentration of Ca(OH)2 = 0.130 mol / 0.250 L = 0.52 M

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2 years ago