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MArishka [77]
3 years ago
13

The Hertzsprung-Russel diagram is used to show the relationship between which two characteristics of stars?

Physics
2 answers:
kykrilka [37]3 years ago
7 0
Between the stars' absolute magnitudes<span> or </span>luminosities<span> versus their </span>stellar classifications<span> or </span>effective temperatures<span>. </span>
larisa [96]3 years ago
5 0
<h3><u>Answer;</u></h3>

Luminosity and temperature of a star

<h3><u>Explanation;</u></h3>
  • <em><u>Hertzsprung-Russel diagram or HR diagram is a scatter plot or a graphical tool that is used by astronomers to classify stars based on their luminosity, color, temperature, spectral type  and also the stage of evolution.</u></em>
  • <em><u>The HR diagram plots the temperature of the stars against the luminosity, or the color of starts against absolute magnitude.</u></em>
  • The HR diagram is divided into stages, for example those stars at the stable phase of hydrogen burning are found within the main sequence according to their mass.
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Let's take two balls, each of radius 0.1 meters and charge them each to 3 microCoulombs. Then, let's put them on a flat surface
salantis [7]

Explanation:

First, we will calculate the electric potential energy of two charges at a distance R as follows.

                   R = 2r

                      = 2 \times 0.1 m

                      = 0.2 m

where,    R = separation between center's of both Q's. Hence, the potential energy will be calculated as follows.

                U = \frac{k \times Q \times Q}{R}

                    = \frac{8.98 \times 10^{9} \times (3 \times 10^{-6} C)^{2}}{0.1}

                    = 0.081 J

As, both the charges are coming towards each other with the same energy so there will occur equal sharing of electric potential energy between these two charges.

Therefore, when these charges touch each other then they used to posses maximum kinetic energy, that is, \frac{U}{2}.

Hence,   K.E = \frac{U}{2}

                     = \frac{0.081}{2}

                     = 0.0405 J

Now, we will calculate the speed of balls as follows.

                 V = \sqrt{\sqrt{\frac{2 \times K.E}{m}}

                     = \sqrt{\sqrt{\frac{2 \times 0.0405}{4 kg}}

                     = 0.142 m/s

Therefore, we can conclude that final speed of one of the balls is 0.142 m/s.

6 0
3 years ago
How does Physics help you as a student?
Sonja [21]

Answer:

The goal of physics is to understand how things work from first principles. ... Courses in physics reveal the mathematical beauty of the universe at scales ranging from subatomic to cosmological. Studying physics strengthens quantitative reasoning and problem solving skills that are valuable in areas beyond physics

8 0
2 years ago
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a brick is suspended above the ground at a height of 6.6 m. it has a mass of 5.3 kg. what is the potential energy of the brick
Svetradugi [14.3K]
The formula for potential energy is
E(p) = mgh

(Mass x gravity x height)

Therefore energy = (5.3)(9.8)(6.6)
= 342.8 J

How did I get 9.8?
9.8 is the constant for gravity
8 0
3 years ago
In the following reaction, which substance is the precipitate? (NH4)2SO4(aq) + Ba(NO3)2(aq) BaSO4(s) + 2NH4NO3(aq) (NH4)2SO4 Ba(
Mariana [72]
I think it's Barium sulfate, the soild and percipitate
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3 years ago
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A 15 n force directed to the west acts on an object for 3.0 seconds, what is the change in momentum of the object?
pickupchik [31]
By definition we have that
 force=dP/dt,
 where
 p is momentum
 so
 <span>momentum is force*time
 p= 15*3 = 45 Ns , west.
 </span><span>the change in momentum of the object is 45 N.s</span>
7 0
3 years ago
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